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TAGS: Director  Joined: 07 Jan 2018
Posts: 604
Followers: 7

Kudos [?]: 546  , given: 88

If the average (arithmetic mean) of seven consecutive intege [#permalink]
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Question Stats: 75% (01:09) correct 25% (01:46) wrong based on 8 sessions
If the average (arithmetic mean) of seven consecutive integers is k + 2, then the product of the greatest and least integer is ?

A. $$k^2$$ – 9

B. $$k^2$$ – 2k + 1

C. $$k^2$$ + 4k – 12

D. $$k^2$$ + 6k + 9

E. $$k^2$$ + 4k – 5
[Reveal] Spoiler: OA
Director Joined: 20 Apr 2016
Posts: 826
WE: Engineering (Energy and Utilities)
Followers: 11

Kudos [?]: 603 , given: 124

Re: If the average (arithmetic mean) of seven consecutive intege [#permalink]
amorphous wrote:
If the average (arithmetic mean) of seven consecutive integers is k + 2, then the product of the greatest and least integer is ?

A. $$k^2$$ – 9

B. $$k^2$$ – 2k + 1

C. $$k^2$$ + 4k – 12

D. $$k^2$$ + 6k + 9

E. $$k^2$$ + 4k – 5

Here
we know k + 2 is the Arithmetic Mean and there are 7 nos

SO the numbers are; K - 1, K , K + 2 , K + 3, K + 4, K + 5

i.e. arithmetic mean = $$\frac{{(K - 1) + (K) + (K + 2) + (K + 3) + (K + 4) + K + 5)}}{7}$$= k + 2

So the greatest number = k + 5 and the smallest number = K - 1

So the product =(k + 5) * (k - 1) = $$k^2$$ + 4k – 5
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Rules for Posting https://greprepclub.com/forum/rules-for ... -1083.html Re: If the average (arithmetic mean) of seven consecutive intege   [#permalink] 27 Jun 2018, 01:39
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