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# If the average (arithmetic mean) of n and 11 is equal to 2n,

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Joined: 07 Jun 2014
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If the average (arithmetic mean) of n and 11 is equal to 2n, [#permalink]  25 Aug 2018, 15:25
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Question Stats:

99% (00:51) correct 0% (00:00) wrong based on 14 sessions
If the average (arithmetic mean) of n and 11 is equal to 2n, what is the average of n and $$\frac{13}{3}$$?

(A) 4
(B) 8
(C) 11
(D) 14
(E) 19
[Reveal] Spoiler: OA

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Director
Joined: 07 Jan 2018
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Kudos [?]: 593 [1] , given: 88

Re: If the average (arithmetic mean) of n and 11 is equal to 2n, [#permalink]  02 Sep 2018, 21:33
1
KUDOS
From question,

$$\frac{n+11}{2} = 2n$$
or, $$n + 11 = 4n$$
solve for n to get, $$n = \frac{11}{3}$$

we are told to get the average of n and 13/3 which means we are required to find the average of 11/3 and 13/3
$$\frac{11}{3} + \frac{13}{3} = \frac{24}{3} = 8$$
therefore, average = 8/2 = 4
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Intern
Joined: 27 Aug 2018
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Kudos [?]: 16 [1] , given: 7

Re: If the average (arithmetic mean) of n and 11 is equal to 2n, [#permalink]  04 Sep 2018, 18:42
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KUDOS
((n+11) / 2) = 2n
==> n = 11/3

The question - what is equally between 11/3 and 13/3? Logically, it is 12/3 = 4
Re: If the average (arithmetic mean) of n and 11 is equal to 2n,   [#permalink] 04 Sep 2018, 18:42
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