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If the average (arithmetic mean) of a, b, c, 5, and 6 is 6, [#permalink]
Expert's post 00:00

Question Stats: 99% (00:36) correct 0% (00:00) wrong based on 17 sessions
If the average (arithmetic mean) of a, b, c, 5, and 6 is 6, what is the average of a, b, c, and 13?

(A) 8
(B) 8.5
(C) 9
(D) 9.5
(E) It cannot be determined from the information given.
[Reveal] Spoiler: OA

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Re: If the average (arithmetic mean) of a, b, c, 5, and 6 is 6, [#permalink]
(a+b+c+5+6)/5=6, so a+b+c+11=30, a+b+c=19.

a+b+c+13=32, average is (a+b+c+13)/4=32/4=8
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Re: If the average (arithmetic mean) of a, b, c, 5, and 6 is 6, [#permalink]
1
KUDOS
The answer is 8.
a+b+c+11 = 30
a+b+c = 19
a+b+c+13 = 32

32/4 = 8 Re: If the average (arithmetic mean) of a, b, c, 5, and 6 is 6,   [#permalink] 04 Sep 2018, 08:54
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If the average (arithmetic mean) of a, b, c, 5, and 6 is 6,  Question banks Downloads My Bookmarks Reviews Important topics Powered by phpBB © phpBB Group Kindly note that the GRE® test is a registered trademark of the Educational Testing Service®, and this site has neither been reviewed nor endorsed by ETS®.