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# If the average (arithmetic mean) of a and b is 6, and a^2

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If the average (arithmetic mean) of a and b is 6, and a^2 [#permalink]  07 Jun 2017, 02:19
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Question Stats:

84% (00:20) correct 15% (00:21) wrong based on 13 sessions

If the average (arithmetic mean) of a and b is 6, and $$a^2 - b^2 = 2$$, what is the value of $$a - b$$ ?

A) $$\frac{1}{6}$$

B) $$\frac{1}{3}$$

C) $$\frac{1}{2}$$

D) 2

E) 3
[Reveal] Spoiler: OA

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Joined: 08 Dec 2017
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Kudos [?]: 37 [1] , given: 70

Re: If the average (arithmetic mean) of a and b is 6, and a^2 [#permalink]  30 Jan 2018, 12:41
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KUDOS
Average of a and b is (a+b)/2=6 or, a+b=12
a^2-b^2=2 or, (a+b)(a-b)=2 or, 12*(a-b)=2 or, a-b = 1/6

Re: If the average (arithmetic mean) of a and b is 6, and a^2   [#permalink] 30 Jan 2018, 12:41
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# If the average (arithmetic mean) of a and b is 6, and a^2

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