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#### Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here. # If the average (arithmetic mean) of 6, 8, 10, and x is betw  Question banks Downloads My Bookmarks Reviews Important topics
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Founder  Joined: 18 Apr 2015
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If the average (arithmetic mean) of 6, 8, 10, and x is betw [#permalink]
Expert's post 00:00

Question Stats: 79% (01:01) correct 20% (02:37) wrong based on 48 sessions

If the average (arithmetic mean) of 6, 8, 10, and x is between 6 and 12, what is the greatest possible integer value of x ?

A) 8

B) 11

C) 20

D) 28

E) 44
[Reveal] Spoiler: OA

_________________ Director Joined: 03 Sep 2017
Posts: 520
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Kudos [?]: 363  , given: 66

Re: If the average (arithmetic mean) of 6, 8, 10, and x is betw [#permalink]
1
KUDOS
The minimum value of the mean is (6+8+10+x)/4 = 6 so that x = 24-6-8-10 = 0. The maximum value, instead, is (6+8+10+x)/4 = 12 so that x = 48-6-8-10 = 24. Thus, the greatest value of x among those reported in the choices is 20. Answer C! Intern Joined: 17 Feb 2018
Posts: 31
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Kudos [?]: 25  , given: 2

Re: If the average (arithmetic mean) of 6, 8, 10, and x is betw [#permalink]
1
KUDOS
we know the mean is between 6 and 12, and we want to know the largest possible integer for X which means the sum of the four number is 44.(since 11 is the largest integer within the range.
6+8+10=24
44-24=20
X=20 Re: If the average (arithmetic mean) of 6, 8, 10, and x is betw   [#permalink] 18 Feb 2018, 18:29
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# If the average (arithmetic mean) of 6, 8, 10, and x is betw  Question banks Downloads My Bookmarks Reviews Important topics Powered by phpBB © phpBB Group Kindly note that the GRE® test is a registered trademark of the Educational Testing Service®, and this site has neither been reviewed nor endorsed by ETS®.