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If the average (arithmetic mean) of 6, 8, 10, and x is betw

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If the average (arithmetic mean) of 6, 8, 10, and x is betw [#permalink] New post 24 May 2017, 02:23
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If the average (arithmetic mean) of 6, 8, 10, and x is between 6 and 12, what is the greatest possible integer value of x ?

A) 8

B) 11

C) 20

D) 28

E) 44
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Re: If the average (arithmetic mean) of 6, 8, 10, and x is betw [#permalink] New post 25 Sep 2017, 06:45
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The minimum value of the mean is (6+8+10+x)/4 = 6 so that x = 24-6-8-10 = 0. The maximum value, instead, is (6+8+10+x)/4 = 12 so that x = 48-6-8-10 = 24. Thus, the greatest value of x among those reported in the choices is 20. Answer C!
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Re: If the average (arithmetic mean) of 6, 8, 10, and x is betw [#permalink] New post 18 Feb 2018, 18:29
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we know the mean is between 6 and 12, and we want to know the largest possible integer for X which means the sum of the four number is 44.(since 11 is the largest integer within the range.
6+8+10=24
44-24=20
X=20
Answer is C.
Re: If the average (arithmetic mean) of 6, 8, 10, and x is betw   [#permalink] 18 Feb 2018, 18:29
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If the average (arithmetic mean) of 6, 8, 10, and x is betw

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