Author 
Message 
TAGS:


Moderator
Joined: 18 Apr 2015
Posts: 4880
Followers: 74
Kudos [?]:
973
[0], given: 4488

If the average (arithmetic mean) of 6, 8, 10, and x is betw [#permalink]
24 May 2017, 02:23
Question Stats:
100% (01:17) correct
0% (00:00) wrong based on 13 sessions
If the average (arithmetic mean) of 6, 8, 10, and x is between 6 and 12, what is the greatest possible integer value of x ? A) 8 B) 11 C) 20 D) 28 E) 44
_________________
Get the 2 FREE GREPrepclub Tests




Director
Joined: 03 Sep 2017
Posts: 521
Followers: 1
Kudos [?]:
327
[1]
, given: 66

Re: If the average (arithmetic mean) of 6, 8, 10, and x is betw [#permalink]
25 Sep 2017, 06:45
1
This post received KUDOS
The minimum value of the mean is (6+8+10+x)/4 = 6 so that x = 246810 = 0. The maximum value, instead, is (6+8+10+x)/4 = 12 so that x = 486810 = 24. Thus, the greatest value of x among those reported in the choices is 20. Answer C!



Intern
Joined: 17 Feb 2018
Posts: 31
Followers: 0
Kudos [?]:
24
[1]
, given: 2

Re: If the average (arithmetic mean) of 6, 8, 10, and x is betw [#permalink]
18 Feb 2018, 18:29
1
This post received KUDOS
we know the mean is between 6 and 12, and we want to know the largest possible integer for X which means the sum of the four number is 44.(since 11 is the largest integer within the range. 6+8+10=24 4424=20 X=20 Answer is C.




Re: If the average (arithmetic mean) of 6, 8, 10, and x is betw
[#permalink]
18 Feb 2018, 18:29





