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# If the average (arithmetic mean) of 5 numbers j, j + 5, 2j –

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If the average (arithmetic mean) of 5 numbers j, j + 5, 2j – [#permalink]  24 Apr 2020, 05:50
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If the average (arithmetic mean) of 5 numbers j, j + 5, 2j – 1, 4j – 2, and 5j – 1 is 8, what is the value of j ?

A. $$\frac{1}{3}$$

B. $$\frac{7}{13}$$

C. 1

D. 3

E. 8
[Reveal] Spoiler: OA

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Re: If the average (arithmetic mean) of 5 numbers j, j + 5, 2j – [#permalink]  24 Apr 2020, 07:35
Expert's post
Carcass wrote:
If the average (arithmetic mean) of 5 numbers j, j + 5, 2j – 1, 4j – 2, and 5j – 1 is 8, what is the value of j ?

A. $$\frac{1}{3}$$

B. $$\frac{7}{13}$$

C. 1

D. 3

E. 8

GIVEN: he average (arithmetic mean) of 5 numbers $$j$$, $$j + 5$$, $$2j – 1$$, $$4j – 2$$, and $$5j – 1$$ is $$8$$

We can write: $$\frac{j + (j+5) + (2j-1) + (4j-2)+ (5j-1)}{5}=8$$

Multiply both sides of the equation by $$5$$ to get: $$j + (j+5) + (2j-1) + (4j-2)+ (5j-1) = 40$$

Simplify to get: $$13j + 1 = 40$$

Subtract $$1$$ from both sides to get: $$13j = 39$$

Divide both sides by $$13$$ to get: $$j = \frac{39}{13}=3$$

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Re: If the average (arithmetic mean) of 5 numbers j, j + 5, 2j –   [#permalink] 24 Apr 2020, 07:35
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