 It is currently 22 Jul 2019, 19:24 ### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

#### Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here. # If the average (arithmetic mean) of 31, 41, and p is between  Question banks Downloads My Bookmarks Reviews Important topics
Author Message
TAGS:
GRE Prep Club Legend  Joined: 07 Jun 2014
Posts: 4809
GRE 1: Q167 V156 WE: Business Development (Energy and Utilities)
Followers: 123

Kudos [?]: 1975 , given: 397

If the average (arithmetic mean) of 31, 41, and p is between [#permalink]
Expert's post 00:00

Question Stats: 66% (00:42) correct 33% (01:06) wrong based on 3 sessions
If the average (arithmetic mean) of 31, 41, and p is between 29 and 47, inclusive, what is the least possible value of $$(p - 7)^2 =$$

Drill 2
Question: 6
Page: 525

[Reveal] Spoiler: OA
64

_________________

Sandy
If you found this post useful, please let me know by pressing the Kudos Button

Try our free Online GRE Test Intern Joined: 26 Aug 2017
Posts: 31
Followers: 0

Kudos [?]: 20  , given: 7

Re: If the average (arithmetic mean) of 31, 41, and p is between [#permalink]
1
KUDOS
I think there's a typo in the question. It should be $$(p - 7)^2$$.

Solution:

To get the least possible value of p, we need p to be as close to 7 as possible.

Of course, because p is contingent on the average, we should form an equation for that:

$$\frac{31 + 41 + p}{3} = X$$

$$p = 3(X) - 72$$

X can be anywhere from 29 to 47 inclusive, but 29 gives the closest possible value to 7, which is 15. The answer is then (15-7)^2 = 64.
GRE Prep Club Legend  Joined: 07 Jun 2014
Posts: 4809
GRE 1: Q167 V156 WE: Business Development (Energy and Utilities)
Followers: 123

Kudos [?]: 1975 , given: 397

Re: If the average (arithmetic mean) of 31, 41, and p is between [#permalink]
Expert's post
You are right!

Fixed it! Thanks
_________________

Sandy
If you found this post useful, please let me know by pressing the Kudos Button

Try our free Online GRE Test

GRE Prep Club Legend  Joined: 07 Jun 2014
Posts: 4809
GRE 1: Q167 V156 WE: Business Development (Energy and Utilities)
Followers: 123

Kudos [?]: 1975 , given: 397

Re: If the average (arithmetic mean) of 31, 41, and p is between [#permalink]
Expert's post
Explanation

To find the least possible value of p, work with the lowest possible average, 29.

Draw an Average Pie. You have 3 values with an average of 29, so your total is 3 × 29 = 87. Now you know that 31 + 41 + p = 87, so p = 15, and (p — 7)2 = 64.

Hence 64 is the correct answer.
_________________

Sandy
If you found this post useful, please let me know by pressing the Kudos Button

Try our free Online GRE Test Re: If the average (arithmetic mean) of 31, 41, and p is between   [#permalink] 29 Dec 2017, 13:27
Display posts from previous: Sort by

# If the average (arithmetic mean) of 31, 41, and p is between  Question banks Downloads My Bookmarks Reviews Important topics Powered by phpBB © phpBB Group Kindly note that the GRE® test is a registered trademark of the Educational Testing Service®, and this site has neither been reviewed nor endorsed by ETS®.