It is currently 08 Dec 2019, 20:39
My Tests

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

If [m](\sqrt[3]{4})([square_root]5.5[/square_root])=([square

  Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:
1 KUDOS received
GRE Instructor
User avatar
Joined: 10 Apr 2015
Posts: 2612
Followers: 95

Kudos [?]: 2818 [1] , given: 45

CAT Tests
If [m](\sqrt[3]{4})([square_root]5.5[/square_root])=([square [#permalink] New post 11 Aug 2019, 10:18
1
This post received
KUDOS
Expert's post
00:00

Question Stats:

58% (03:40) correct 41% (01:55) wrong based on 12 sessions
If \((\sqrt[3]{4})(\sqrt{5.5})=(\sqrt{22})(\sqrt[3]{x})\), then \(x=\)

A) \(\frac{1}{8}\)

B) \(\frac{1}{2}\)

C) \(1\)

D) \(\sqrt[3]{2}\)

e) \(2\)
[Reveal] Spoiler: OA

_________________

Brent Hanneson – Creator of greenlighttestprep.com
Sign up for my free GRE Question of the Day emails

1 KUDOS received
GRE Instructor
User avatar
Joined: 10 Apr 2015
Posts: 2612
Followers: 95

Kudos [?]: 2818 [1] , given: 45

CAT Tests
Re: If [m](\sqrt[3]{4})([square_root]5.5[/square_root])=([square [#permalink] New post 11 Aug 2019, 10:21
1
This post received
KUDOS
Expert's post
GreenlightTestPrep wrote:
If \((\sqrt[3]{4})(\sqrt{5.5})=(\sqrt{22})(\sqrt[3]{x})\), then \(x=\)

A) \(\frac{1}{8}\)

B) \(\frac{1}{2}\)

C) \(1\)

D) \(\sqrt[3]{2}\)

e) \(2\)


Useful root property: \(\frac{\sqrt[n]{x}}{\sqrt[n]{y}}=\sqrt[n]{\frac{x}{y}}\)

Given: \((\sqrt[3]{4})(\sqrt{5.5})=(\sqrt{22})(\sqrt[3]{x})\)

Divide both sides by \(\sqrt{5.5}\) to get: \(\sqrt[3]{4}=\frac{(\sqrt{22})(\sqrt[3]{x})}{\sqrt{5.5}}\)

Divide both sides by \(\sqrt[3]{x}\) to get: \(\frac{\sqrt[3]{4}}{\sqrt[3]{x}}=\frac{\sqrt{22}}{\sqrt{5.5}}\)

Apply above property to both sides to get: \(\sqrt[3]{\frac{4}{x}}=\sqrt{\frac{22}{5.5}}\)

Simplify right side: \(\sqrt[3]{\frac{4}{x}}=\sqrt{4}\)

Simplify right side: \(\sqrt[3]{\frac{4}{x}}=2\)

Raise both sides to the power of 3 to get: \((\sqrt[3]{\frac{4}{x}})^3=2^3\)

Simplify: \(\frac{4}{x} = 8\)

Solve: \(x = \frac{4}{8} = \frac{1}{2}\)

Answer: B

Cheers,
Brent
_________________

Brent Hanneson – Creator of greenlighttestprep.com
Sign up for my free GRE Question of the Day emails

Senior Manager
Senior Manager
User avatar
Joined: 22 Jun 2019
Posts: 379
Followers: 0

Kudos [?]: 51 [0], given: 137

CAT Tests
Re: If [m](\sqrt[3]{4})([square_root]5.5[/square_root])=([square [#permalink] New post 12 Aug 2019, 01:42
GreenlightTestPrep wrote:
GreenlightTestPrep wrote:
If \((\sqrt[3]{4})(\sqrt{5.5})=(\sqrt{22})(\sqrt[3]{x})\), then \(x=\)

A) \(\frac{1}{8}\)

B) \(\frac{1}{2}\)

C) \(1\)

D) \(\sqrt[3]{2}\)

e) \(2\)


Useful root property: \(\frac{\sqrt[n]{x}}{\sqrt[n]{y}}=\sqrt[n]{\frac{x}{y}}\)

Given: \((\sqrt[3]{4})(\sqrt{5.5})=(\sqrt{22})(\sqrt[3]{x})\)

Divide both sides by \(\sqrt{5.5}\) to get: \(\sqrt[3]{4}=\frac{(\sqrt{22})(\sqrt[3]{x})}{\sqrt{5.5}}\)

Divide both sides by \(\sqrt[3]{x}\) to get: \(\frac{\sqrt[3]{4}}{\sqrt[3]{x}}=\frac{\sqrt{22}}{\sqrt{5.5}}\)

Apply above property to both sides to get: \(\sqrt[3]{\frac{4}{x}}=\sqrt{\frac{22}{5.5}}\)

Simplify right side: \(\sqrt[3]{\frac{4}{x}}=\sqrt{4}\)

Simplify right side: \(\sqrt[3]{\frac{4}{x}}=2\)

Raise both sides to the power of 3 to get: \((\sqrt[3]{\frac{4}{x}})^3=2^2\)

Simplify: \(\frac{4}{x} = 8\)

Solve: \(x = \frac{4}{8} = \frac{1}{2}\)

Answer: B

Cheers,
Brent


I think,seems little mistake in the last portion. It will be
Corrected line: Raise both sides to the power of 3 to get: \((\sqrt[3]{\frac{4}{x}})^3=2^3\)
1 KUDOS received
VP
VP
Joined: 20 Apr 2016
Posts: 1087
WE: Engineering (Energy and Utilities)
Followers: 16

Kudos [?]: 942 [1] , given: 226

Re: If [m](\sqrt[3]{4})([square_root]5.5[/square_root])=([square [#permalink] New post 12 Aug 2019, 07:12
1
This post received
KUDOS
GreenlightTestPrep wrote:
If \((\sqrt[3]{4})(\sqrt{5.5})=(\sqrt{22})(\sqrt[3]{x})\), then \(x=\)

A) \(\frac{1}{8}\)

B) \(\frac{1}{2}\)

C) \(1\)

D) \(\sqrt[3]{2}\)

e) \(2\)


Here,
\((\sqrt[3]{4})(\sqrt{5.5})=(\sqrt{22})(\sqrt[3]{x})\)

or \((\sqrt[3]{4}) * 2.3 = 4.6* (\sqrt[3]{x})\) { use of calculator to find \(\sqrt{5.5}\) and \(\sqrt{22}\) }

or \((\sqrt[3]{4}) = 2 * (\sqrt[3]{x})\) (dividing both sides by 2.3)

Cubing both sides
\(4 = 8* x\)

or \(x = \frac{1}{2}\)
_________________

If you found this post useful, please let me know by pressing the Kudos Button


Rules for Posting

Got 20 Kudos? You can get Free GRE Prep Club Tests

GRE Prep Club Members of the Month:TOP 10 members of the month with highest kudos receive access to 3 months GRE Prep Club tests

Senior Manager
Senior Manager
User avatar
Joined: 22 Jun 2019
Posts: 379
Followers: 0

Kudos [?]: 51 [0], given: 137

CAT Tests
Re: If [m](\sqrt[3]{4})([square_root]5.5[/square_root])=([square [#permalink] New post 12 Aug 2019, 07:37
pranab01 wrote:
GreenlightTestPrep wrote:
If \((\sqrt[3]{4})(\sqrt{5.5})=(\sqrt{22})(\sqrt[3]{x})\), then \(x=\)

A) \(\frac{1}{8}\)

B) \(\frac{1}{2}\)

C) \(1\)

D) \(\sqrt[3]{2}\)

e) \(2\)


Here,
\((\sqrt[3]{4})(\sqrt{5.5})=(\sqrt{22})(\sqrt[3]{x})\)

or \((\sqrt[3]{4}) * 2.3 = 4.6* (\sqrt[3]{x})\) { use of calculator to find \(\sqrt{5.5}\) and \(\sqrt{22}\) }

or \((\sqrt[3]{4}) = 2 * (\sqrt[3]{x})\) (dividing both sides by 2.3)

Cubing both sides
\(4 = 8* x\)

or \(x = \frac{1}{2}\)



I THINK GRE CALCULATOR DOES NOT ALLOW TO CALCULATE ROOT EITHER, SO WE NEED TO PASS IT.
GRE Instructor
User avatar
Joined: 10 Apr 2015
Posts: 2612
Followers: 95

Kudos [?]: 2818 [0], given: 45

CAT Tests
Re: If [m](\sqrt[3]{4})([square_root]5.5[/square_root])=([square [#permalink] New post 12 Aug 2019, 08:20
Expert's post
huda wrote:
I think,seems little mistake in the last portion. It will be
Corrected line: Raise both sides to the power of 3 to get: \((\sqrt[3]{\frac{4}{x}})^3=2^3\)


Good catch - thanks!
I've changed the exponent.

Kudos for you!!

Cheers,
Brent
_________________

Brent Hanneson – Creator of greenlighttestprep.com
Sign up for my free GRE Question of the Day emails

1 KUDOS received
GRE Instructor
User avatar
Joined: 10 Apr 2015
Posts: 2612
Followers: 95

Kudos [?]: 2818 [1] , given: 45

CAT Tests
Re: If [m](\sqrt[3]{4})([square_root]5.5[/square_root])=([square [#permalink] New post 12 Aug 2019, 08:24
1
This post received
KUDOS
Expert's post
huda wrote:
pranab01 wrote:
GreenlightTestPrep wrote:
If \((\sqrt[3]{4})(\sqrt{5.5})=(\sqrt{22})(\sqrt[3]{x})\), then \(x=\)

A) \(\frac{1}{8}\)

B) \(\frac{1}{2}\)

C) \(1\)

D) \(\sqrt[3]{2}\)

e) \(2\)


Here,
\((\sqrt[3]{4})(\sqrt{5.5})=(\sqrt{22})(\sqrt[3]{x})\)

or \((\sqrt[3]{4}) * 2.3 = 4.6* (\sqrt[3]{x})\) { use of calculator to find \(\sqrt{5.5}\) and \(\sqrt{22}\) }

or \((\sqrt[3]{4}) = 2 * (\sqrt[3]{x})\) (dividing both sides by 2.3)

Cubing both sides
\(4 = 8* x\)

or \(x = \frac{1}{2}\)



I THINK GRE CALCULATOR DOES NOT ALLOW TO CALCULATE ROOT EITHER, SO WE NEED TO PASS IT.


pranab01 is estimating those roots.
It's a good strategy.

By the way, the GRE's onscreen calculator does have a square root button.
Here's my video on this
[you-tube]https://youtu.be/qvL9uwnR0v8[/you-tube]

Cheers,
Brent
_________________

Brent Hanneson – Creator of greenlighttestprep.com
Sign up for my free GRE Question of the Day emails

Re: If [m](\sqrt[3]{4})([square_root]5.5[/square_root])=([square   [#permalink] 12 Aug 2019, 08:24
Display posts from previous: Sort by

If [m](\sqrt[3]{4})([square_root]5.5[/square_root])=([square

  Question banks Downloads My Bookmarks Reviews Important topics  


GRE Prep Club Forum Home| About| Terms and Conditions and Privacy Policy| GRE Prep Club Rules| Contact

Powered by phpBB © phpBB Group

Kindly note that the GRE® test is a registered trademark of the Educational Testing Service®, and this site has neither been reviewed nor endorsed by ETS®.