Let \(k\) be an integer such that \(\frac{p}{9} + \frac{q}{10} = k\).

Since all three numbers \(p\), \(q\), and \(k\) are integers, among the given options, the only case could be:
integer \((\frac{p}{9})\) + integer \((\frac{q}{10})\) = integer \((k)\)

C wins
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