JelalHossain wrote:

I did the backward calculation by taking the possible values of K. I tried to find whether the reformed equation ( in line with the value of K) gives two roots or not and the roots corroborate to the conditions or not. Eventually , whiling taking K=-1/3, It matched the conditions. Thus, I got C.

But this was too time-consuming.

Can any of you please give an easy and quicker solution ?

Regards

The solution provided above is less time consuming.

Whenever u receive a complex quadratic equation "\(ax^2 + bx + C\) " and need to find the roots, the best way is to know

1. Sum of the roots = \(-\frac{b}{a}\)

2. product of the roots = \(\frac{c}{a}\)

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