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TAGS: Director  Joined: 07 Jan 2018
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If n is a multiple of 5 and n = p [#permalink]
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Question Stats: 61% (01:14) correct 38% (02:52) wrong based on 26 sessions
If n is a multiple of 5 and n = $$P^2Q$$, where P and Q are prime number. Which of the following must be a multiple of 25?

A $$P^2$$

B $$Q^2$$

C $$PQ$$

D $$P^2*Q^2$$

E $$P^3Q$$

source: orbit test prep
[Reveal] Spoiler: OA Director Joined: 20 Apr 2016
Posts: 907
WE: Engineering (Energy and Utilities)
Followers: 11

Kudos [?]: 671  , given: 148

Re: If n is a multiple of 5 and n = p [#permalink]
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amorphous wrote:
If n is a multiple of 5 and n = P^2Q, where P and Q are prime number. Which of the following must be a multiple of 25?

Can you please look into the question -

Does it mean $$n = P^{2Q}$$

or $$n = {P^2}Q$$
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Rules for Posting https://greprepclub.com/forum/rules-for ... -1083.html Director  Joined: 07 Jan 2018
Posts: 644
Followers: 7

Kudos [?]: 602  , given: 88

Re: If n is a multiple of 5 and n = p [#permalink]
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pranab01 wrote:
amorphous wrote:
If n is a multiple of 5 and n = P^2Q, where P and Q are prime number. Which of the following must be a multiple of 25?

Can you please look into the question -

Does it mean $$n = P^{2Q}$$

or $$n = {P^2}Q$$

I have made the modification it is the second one.
Intern Joined: 21 Jun 2018
Posts: 35
Followers: 0

Kudos [?]: 6 , given: 11

Re: If n is a multiple of 5 and n = p [#permalink]
amorphous wrote:
If n is a multiple of 5 and n = $$P^2Q$$, where P and Q are prime number. Which of the following must be a multiple of 25?

A $$P^2$$

B $$Q^2$$

C $$PQ$$

D $$P^2*Q^2$$

E $$P^3Q$$

source: orbit test prep Director  Joined: 07 Jan 2018
Posts: 644
Followers: 7

Kudos [?]: 602  , given: 88

Re: If n is a multiple of 5 and n = p [#permalink]
2
KUDOS
N is a multiple of 5 so either P or Q or both have to be 5.

We are looking for a multiple of 25 so,

Among the given option the right ans should be a multiple of 25 and not simply be 5, 10 or 15 or other multiples of 5 but not a multiple of 25.

It could be that P^2 = 2^2 and Q = 5. Since this would result in N becoming a multiple of 5 but not a multiple of 25 option A is wrong
For option B
we can reverse the scenario such that P = 5 and Q =2; Yet this will be a multiple of 5 but not a multiple of 25

For option C
If we take the same two value 5 and 2 we get PQ = 10 and yet this will not be a multiple of 25

For option D

If anyone of P and Q is 5 this will be a multiple of 5 because both P and Q are squared hence 5^2 = 25 and this will be divisible by 25.
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This is my response to the question and may be incorrect. Feel free to rectify any mistakes Re: If n is a multiple of 5 and n = p   [#permalink] 13 Aug 2018, 06:02
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