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# If K > 0

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Joined: 20 Apr 2016
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Kudos [?]: 522 [0], given: 94

If K > 0 [#permalink]  30 Nov 2018, 10:31
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Question Stats:

100% (00:23) correct 0% (00:00) wrong based on 6 sessions
If K > 0

 Quantity A Quantity B $$\frac{{5k^2-1}}{{2k^3}}$$ $$\frac{5}{2k}$$

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

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Last edited by Carcass on 30 Nov 2018, 10:35, edited 1 time in total.
Edited by Carcass
GRE Instructor
Joined: 10 Apr 2015
Posts: 1254
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Kudos [?]: 1160 [0], given: 7

Re: If K > 0 [#permalink]  30 Nov 2018, 13:18
Expert's post
pranab01 wrote:
If K > 0

 Quantity A Quantity B $$\frac{{5k^2-1}}{{2k^3}}$$ $$\frac{5}{2k}$$

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

Since k is positive, we know that 2k³ is POSITIVE
This means we can safely multiply both quantities by 2k³ to get:
Quantity A: 5k² - 1
Quantity B: 10k³/2k

Simplify Quantity B to get:
Quantity A: 5k² - 1
Quantity B: 5k²

Subtract 5k² from both quantities to get:
Quantity A: -1
Quantity B: 0

Quantity B is greater.

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Re: If K > 0   [#permalink] 30 Nov 2018, 13:18
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