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If K > 0

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If K > 0 [#permalink] New post 30 Nov 2018, 10:31
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Question Stats:

100% (00:23) correct 0% (00:00) wrong based on 6 sessions
If K > 0

Quantity A
Quantity B
\(\frac{{5k^2-1}}{{2k^3}}\)
\(\frac{5}{2k}\)




A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

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Last edited by Carcass on 30 Nov 2018, 10:35, edited 1 time in total.
Edited by Carcass
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Re: If K > 0 [#permalink] New post 30 Nov 2018, 13:18
Expert's post
pranab01 wrote:
If K > 0

Quantity A
Quantity B
\(\frac{{5k^2-1}}{{2k^3}}\)
\(\frac{5}{2k}\)




A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.


Since k is positive, we know that 2k³ is POSITIVE
This means we can safely multiply both quantities by 2k³ to get:
Quantity A: 5k² - 1
Quantity B: 10k³/2k

Simplify Quantity B to get:
Quantity A: 5k² - 1
Quantity B: 5k²

Subtract 5k² from both quantities to get:
Quantity A: -1
Quantity B: 0

Quantity B is greater.

Answer: B

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Re: If K > 0   [#permalink] 30 Nov 2018, 13:18
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