sandy wrote:

If \(g(x) = \frac{x^2(4x+9)}{(3x-3)(x+2)}\), for which of the following x values is g(x) undefined?

Indicate all such values of x.

A. \(\frac{-9}{4}\)

B. \(–2\)

C. \(0\)

D. \(1\)

E. \(2\)

F. \(\frac{9}{4}\)

A rational expression (aka fraction) is considered undefined

when the denominator is zeroIn this question the denominator is (3x-3)(x+2)

So, the denominator will equal zero when (3x-3) = 0 or (x+2) = 0

Let's examine each case separately.

If (3x-3) = 0, the x = 1

If (x+2) = 0, the x = -2

So, when x = 1, the fraction is undefined.

Likewise, when x = -2, the fraction is undefined.

Answer: B, D

Cheers,

Brent

_________________

Brent Hanneson – Creator of greenlighttestprep.com

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