Carcass wrote:

If f footballs cost d dollars, then in terms of d and f how many dollars would 10 footballs cost?

A. \(10 f d\)

B.\(f\frac{d}{10}\)

C. \(10\frac{d}{f}\)

D. \(d\frac{f}{10}\)

E. \(f\frac{d}{10}\)

If f footballs cost d dollars...With this info, how much does ONE football cost?

If you're not sure, try testing some values.

For example, if 3 footballs cost 15 dollars, then ONE football costs 5 dollars (aka 15/3 dollars)

If 7 footballs cost 28 dollars, then ONE football costs 4 dollars (aka 28/7 dollars)

If 10 footballs cost 80 dollars, then ONE football costs 8 dollars (aka 80/8 dollars)

See the pattern?

If f footballs cost d dollars, then ONE football costs

d/f dollars

If ONE football costs

d/f dollars, then

TWO football costs

(2)(d/f) dollars

If ONE football costs

d/f dollars, then

THREE football costs

(3)(d/f) dollars

.

.

.

If ONE football costs

d/f dollars, then

TEN football costs

(10)(d/f) dollars

Answer: C

Cheers,

Brent

_________________

Brent Hanneson – Creator of greenlighttestprep.com

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