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If each of the three nonzero numbers a, b, and c is divisibl [#permalink]
 21 Apr 2018, 04:58
Question Stats:
87% (00:16) correct
12% (00:57) wrong based on 24 sessions
If each of the three nonzero numbers a, b, and c is divisible by 3, then abc must be divisible by which one of the following the numbers? (A) 8 (B) 27 (C) 81 (D) 121 (E) 159
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Re: If each of the three nonzero numbers a, b, and c is divisibl [#permalink]
25 Apr 2018, 01:53
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\(A,B, and C\) are non zero integer divisible by \(3\)so at minimum \(a=3,b=3,c=3\) therefore abc at minimum \(= 27\) and abc should be a multiple of \(27\) option B
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Re: If each of the three nonzero numbers a, b, and c is divisibl [#permalink]
07 Apr 2019, 17:45
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Carcass wrote: If each of the three nonzero numbers a, b, and c is divisible by 3, then abc must be divisible by which one of the following the numbers?
(A) 8
(B) 27
(C) 81
(D) 121
(E) 159 We see that a = 3r, b = 3s and c = 3t for some nonzero integers r, s, and t. Therefore, abc = (3r)(3s)(3t) = 27rst. We see that abc must be divisible by 27. Answer: B
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Re: If each of the three nonzero numbers a, b, and c is divisibl
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07 Apr 2019, 17:45
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