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# If d-3n/7n-d=1

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If d-3n/7n-d=1 [#permalink]  29 Dec 2016, 09:19
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81% (00:40) correct 18% (01:40) wrong based on 11 sessions
If $$\frac{d-3n}{7n-d}=1$$, which of the following must be true about the relationship between d and n ?

(A) n is 4 more than d

(B) d is 4 more than n

(C) n is $$\frac{7}{3}$$ of d

(D) d is 5 times n

(E) d is 2 times n
[Reveal] Spoiler: OA

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Re: If d-3n/7n-d=1 [#permalink]  29 Sep 2017, 06:53
The idea here is to solve the equation until we get d on one side of the equal sign and n on the other.

Then, $$\frac{d-3n}{7n-d}-1=0$$. Taking the MCM, we get $$\frac{d-3n-7n+d}{7n-d}=0$$. Getting rid of the deniminator and simplyfing we get $$d=5n$$. Thus, d is 5 times n.

Re: If d-3n/7n-d=1   [#permalink] 29 Sep 2017, 06:53
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# If d-3n/7n-d=1

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