sandy wrote:
If \(b=\frac{4a}{c}\) , a is halved, and c is doubled, by what percentage will b decrease?
A. 4%
B. 25%
C. 50%
D. 75%
E. 100%
Here let take a=10 , c= 2 (for easy calculation we want to keep the value of b as integer and not fraction)
so b =\(\frac{(4 * 10)}{(2)}\)
or b= 20
Now a is halved = \(\frac{10}{2}\) = 5
and c is doubled = 2+2 = 4
Now b= \(\frac{(4 * 5)}{(4)}\) = 5
Therefore percentage decrease = \(\frac{(5-20)}{20}* 100\) = -75% i.e decrease
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