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# If a square region with side x and a circular region with ra

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If a square region with side x and a circular region with ra [#permalink]  09 Dec 2017, 16:25
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73% (00:28) correct 26% (00:35) wrong based on 23 sessions
If a square region with side x and a circular region with radius r have the same area, then x must be how many times as great as r?

A. $$\frac{1}{\pi}$$

B. $$\frac{1}{sqrt\pi}$$

C. $$\sqrt{\pi}$$

D. $$\pi$$

E. $$\pi^2$$
[Reveal] Spoiler: OA

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Re: If a square region with side x and a circular region with ra [#permalink]  25 Jan 2018, 03:55
How to do this question?
Why not B
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Re: If a square region with side x and a circular region with ra [#permalink]  25 Jan 2018, 04:09
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\sqrt{pi} is the correct answer.
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Re: If a square region with side x and a circular region with ra [#permalink]  28 Mar 2018, 22:41
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X^2=pi(r^2) then square root both equations and get x= (square root pi) * r and we can see that x is greater than r in (square root pi)
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Re: If a square region with side x and a circular region with ra   [#permalink] 28 Mar 2018, 22:41
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# If a square region with side x and a circular region with ra

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