Carcass wrote:

If a ≤ b ≤ c ≤ d ≤ e ≤ 110 and the average (arithmetic mean) of a, b, c, d, and e is 100, what is the least possible value of a?

A) 0

B) 20

C) 40

D) 60

E) 80

The average (arithmetic mean) of a, b, c, d, and e is 100So, (a + b + c + d + e)/5 = 100

This means

a + b + c + d + e = 500What is the least possible value of a? We already know that

a + b + c + d + e = 500So, to MINIMIZE the value of a, we must MAXIMIZE the values of b, c, d, and e

Since a ≤ b ≤ c ≤ d ≤ e ≤ 110, the MAXIMUM value of b, c, d, and e is 110

Take:

a + b + c + d + e = 500Replace b, c, d and e with 110 to get:

a + 110 + 110 + 110 + 110 = 500Simplify:

a + 440 = 500Solve:

a = 60Answer: D

Cheers,

Brent

_________________

Brent Hanneson – Creator of greenlighttestprep.com

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