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If a, b, c, and d are consecutive integers and a < b < c < d

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sandy

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Joined: 07 Jun 2014

Posts: 4805

GRE 1: Q167 V156

WE:Business Development (Energy and Utilities)

If a, b, c, and d are consecutive integers and a < b < c < d [#permalink]

19 Aug 2018, 03:52

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If a, b, c, and d are consecutive integers and a < b < c < d, what is the average (arithmetic mean) of a, b, c, and d in terms of d?

(A) \(d - \frac{5}{2}\)
(B) \(d - 2\)
(C) \(d - \frac{3}{2}\)
(D) \(d + \frac{3}{2}\)
(E) \(\frac{4d-6}{7}\)

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ARIJOSHI

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Joined: 07 Jan 2019

Posts: 38

Re: If a, b, c, and d are consecutive integers and a < b < c < d [#permalink]

16 Jan 2019, 07:35

If a, b, c, and d are consecutive integers and a < b < c < d, what is the average (arithmetic mean) of a, b, c, and d in terms of d?

Given that,

a < b < c < d

a, b, c and d are consecutive integers, so, let us suppose, a = d-3, b = d-2, c = d-1 and d = d

Average ( arithmetic mean) = a + b + c + d/ 4

= (d-3 + d-2 + d-1 + d) /4

By calculation, we get, d = 2d-3/2.

Thus, answer is C.