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Another approach is to PLUG IN some numbers that satisfy the given conditions.

Given: a = b x c² So, how about a = 2500, b = 100 and c = 5 We get: 2500 = 100 x 5²

c decreases by 20% while a remains constant c becomes 4 and a stays at 2500 So, we get: 2500 = b x 4² Simplify: 2500 = b x 16 Solve: 2500/16 = b Simplify: 156.25 = b

So b INCREASES from 100 to 156.25 This represents an increase of 56.25% Since the question asks us to round our answer to the nearest TENTH, the correct response is 56.3

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Re: If a = b × c^2 and c decreases by 20% while a remains
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11 Jul 2017, 04:09