As it is mentioned
a, b and x are integers greater than zero

so a,b,x can be equal, consecutive numbers or any other possible value matching the criteria.

Now we can glance down straight to the answer choice we can eliminate option B, D and E. Option A is the possible contender.

Option B : if x is subtracted from numerator than the value will be < \(\frac{a}{a+b}\)
Option D : we are squaring the value but remember we are also squaring the denominator so the value will be < \(\frac{a}{a+b}\)
Option E: Again if 1` is subtracted it will only reduce the value so it will always be < \(\frac{a}{a+b}\)

Now for option C:: Let dig some value such as all numbers are considered equal, after solving it < \(\frac{a}{a+b}\)

So only option left is A, we can put some value such as a = b =c = x =1, or any integer value greater than 1, it will always be > \(\frac{a}{a+b}\)
_________________

If you found this post useful, please let me know by pressing the Kudos Button


Rules for Posting

Got 20 Kudos? You can get Free GRE Prep Club Tests

GRE Prep Club Members of the Month:TOP 10 members of the month with highest kudos receive access to 3 months GRE Prep Club tests