It is currently 22 Mar 2019, 08:06

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# If a, b, and c are multiples of 3 such that a > b > c > 0, w

Author Message
TAGS:
GRE Prep Club Legend
Joined: 07 Jun 2014
Posts: 4857
GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
Followers: 105

Kudos [?]: 1778 [0], given: 397

If a, b, and c are multiples of 3 such that a > b > c > 0, w [#permalink]  12 Aug 2018, 16:08
Expert's post
00:00

Question Stats:

100% (00:34) correct 0% (00:00) wrong based on 3 sessions
If a, b, and c are multiples of 3 such that a > b > c > 0, which of the following values must be divisible by 3?

Indicate all such values.
A. a + b + c
B. a – b + c
C. $$\frac{abc}{9}$$
[Reveal] Spoiler: OA

_________________

Sandy
If you found this post useful, please let me know by pressing the Kudos Button

Try our free Online GRE Test

GRE Prep Club Legend
Joined: 07 Jun 2014
Posts: 4857
GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
Followers: 105

Kudos [?]: 1778 [0], given: 397

Re: If a, b, and c are multiples of 3 such that a > b > c > 0, w [#permalink]  17 Aug 2018, 16:00
Expert's post
Explanation

Since a, b, and c are all multiples of 3, a = 3x, b = 3y, c = 3z, where x > y > z > 0 and all are integers.

Substitute these new expressions into the statements.

First statement: $$a + b + c = 3x + 3y + 3z = 3(x + y + z)$$. Since (x + y + z) is an integer, this number must be divisible by 3.

Second statement: $$a - b + c = 3x - 3y + 3z = 3(x - y + z)$$. Since (x + y + z) is an integer, this number must be divisible by 3.

Third statement:$$\frac{abc}{9}=\frac{3x \times 3y \times 3z}{9}=\frac{27xyz}{9}= 3xyz$$. Since xyz is an integer, this number must be divisible by 3.
_________________

Sandy
If you found this post useful, please let me know by pressing the Kudos Button

Try our free Online GRE Test

Re: If a, b, and c are multiples of 3 such that a > b > c > 0, w   [#permalink] 17 Aug 2018, 16:00
Display posts from previous: Sort by