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# If a, b, and c are integers

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If a, b, and c are integers [#permalink]  08 Jun 2019, 04:41
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Question Stats:

0% (00:00) correct 100% (01:13) wrong based on 3 sessions
If a, b, and c are integers and $$\frac{ab^2}{c}$$ is a positive even integer, which of the following must be true?

I. ab is even
II. ab > 0
III. c is even

A. I only
B. II only
C. I and II
D. I and III
E. I, II, and III
[Reveal] Spoiler: OA
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Re: If a, b, and c are integers [#permalink]  10 Jun 2019, 08:49
Expert's post
dvk007 wrote:
If a, b, and c are integers and $$\frac{ab^2}{c}$$ is a positive even integer, which of the following must be true?

I. ab is even
II. ab > 0
III. c is even

A. I only
B. II only
C. I and II
D. I and III
E. I, II, and III

Statement I. ab is even

GIVEN: $$\frac{ab^2}{c}$$ is an even integer

This means we can say that $$\frac{ab^2}{c}$$ = 2k (for some integer k)

Multiply both sides by c to get: $$ab^2 = 2kc$$

We can see that 2kc must be EVEN, which means ab^2 must be EVEN.
If ab^2 is EVEN, then either a or b must be EVEN, which means ab must be EVEN
So statement I is true

---------------------------

Statement II. ab > 0
Notice that, regardless of the value of b, we know that b² is POSITIVE (for all non-zero values of b)
This leads me to test some possible values...

If $$\frac{ab^2}{c}$$ is a positive even integer, then it COULD be the case that a = 2, b = -1 and c = 1
Notice that $$\frac{ab^2}{c}=\frac{(2)(-1)^2}{1}=2$$, which is a positive even integer

In this case, ab = (2)(-1) = -2
So, it is NOT true that ab > 0
So statement II is NOT true

Check the answer choices....ELIMINATE C and E
-------------------------------

Statement III. c is even
Notice that we can reuse the values we used above (a = 2, b = -1 and c = 1)
If c = 1, then c is NOT even
So statement III is NOT true

Cheers,
Brent
_________________

Brent Hanneson – Creator of greenlighttestprep.com

Re: If a, b, and c are integers   [#permalink] 10 Jun 2019, 08:49
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