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# If (a+2b)/(17b-2a)=1

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If (a+2b)/(17b-2a)=1 [#permalink]  27 Aug 2018, 13:53
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Question Stats:

56% (00:38) correct 44% (00:53) wrong based on 25 sessions
If $$\frac{(a+2b)}{(17b-2a)}=1$$, which of the following must be true about the relationship between a and b?

A. a is 3 more than b.

B. b is 3 more than a.

C. a is $$\frac{1}{5}$$ of b.

D. a is 5 times b.

E. a is $$\frac{3}{5}$$ of b.
[Reveal] Spoiler: OA

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Re: If (a+2b)/(17b-2a)=1 [#permalink]  28 Aug 2018, 06:43
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Solving equation we get the answer a = 5b (D)
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Re: If (a+2b)/(17b-2a)=1 [#permalink]  28 Aug 2018, 11:01
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Carcass wrote:
If $$\frac{(a+2b)}{(17b-2a)}=1$$, which of the following must be true about the relationship between a and b?

A. a is 3 more than b.

B. b is 3 more than a.

C. a is $$\frac{1}{5}$$ of b.

D. a is 5 times b.

E. a is $$\frac{3}{5}$$ of b.

Given: (a + 2b)/(17b - 2a) = 1
Multiply both side by (17b - 2a) to get: = a + 2b = 17b - 2a
Subtract 2b from both sides to get: a = 15b - 2a
Add 2a to both sides to get: 3a = 15b
Divide both sides by 3 to get: a = 5b (a equals 5 times b)

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Brent
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Re: If (a+2b)/(17b-2a)=1   [#permalink] 28 Aug 2018, 11:01
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