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If a = 2, b = 4, and c= 5, then

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If a = 2, b = 4, and c= 5, then [#permalink] New post 28 Jun 2020, 10:00
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If \(a = 2\), \(b = 4\), and \(c= 5\), then \(\frac{a+b}{c} - \frac{c}{a+b} =
\)


A. 1

B. 11/30

C. 0

D. -11/30

E. -1
[Reveal] Spoiler: OA

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Re: If a = 2, b = 4, and c= 5, then [#permalink] New post 28 Jun 2020, 10:40
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We put the values of a,b,c in the equation given below and we get

\(\frac{2+4}{5} - \frac{5}{2+4}\)

= \(\frac{6}{5} - \frac{5}{6}\)

Now we can take the LCM of the denominators of these fractions and solve it.
But, let's see another method.
We know that \(\frac{6}{5} = 1.2\)

and \(\frac{5}{6}\) is a little less than.

So, 1.2 - (little less than 1) cannot be negative. It can neither be 0 nor 1.

OA, B
Carcass wrote:
If \(a = 2\), \(b = 4\), and \(c= 5\), then \(\frac{a+b}{c} - \frac{c}{a+b} =
\)


A. 1

B. 11/30

C. 0

D. -11/30

E. -1

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Re: If a = 2, b = 4, and c= 5, then [#permalink] New post 28 Jun 2020, 15:10
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Plugging the values into the equation, we get
\(\frac{6}{5 }\) - \(\frac{ 5}{6}\) we need to find the lowest common multiple for the denominators to compute the fraction. The lowest common multiple is 30.

Multiply \(\frac{6}{5}\) * \(\frac{6}{6}\) = \(\frac{36}{30}\)
multiply \(\frac{5}{6}\) * \(\frac{5}{5}\) = \(\frac{25}{30}\)

Then we get \(\frac{36}{30}\) - \(\frac{25}{30}\) = \(\frac{11}{30}\)
Answer choice B
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Re: If a = 2, b = 4, and c= 5, then [#permalink] New post 04 Jul 2020, 12:51
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By plugging the given values
6/5-5/6
multiply the whole by 30

36-25=11
Hence 11/30

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Re: If a = 2, b = 4, and c= 5, then   [#permalink] 04 Jul 2020, 12:51
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If a = 2, b = 4, and c= 5, then

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