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# If a = 2, b = 4, and c= 5, then

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If a = 2, b = 4, and c= 5, then [#permalink]  28 Jun 2020, 10:00
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If $$a = 2$$, $$b = 4$$, and $$c= 5$$, then $$\frac{a+b}{c} - \frac{c}{a+b} =$$

A. 1

B. 11/30

C. 0

D. -11/30

E. -1
[Reveal] Spoiler: OA

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Kudos [?]: 165 [2] , given: 5

Re: If a = 2, b = 4, and c= 5, then [#permalink]  28 Jun 2020, 10:40
2
KUDOS
We put the values of a,b,c in the equation given below and we get

$$\frac{2+4}{5} - \frac{5}{2+4}$$

= $$\frac{6}{5} - \frac{5}{6}$$

Now we can take the LCM of the denominators of these fractions and solve it.
But, let's see another method.
We know that $$\frac{6}{5} = 1.2$$

and $$\frac{5}{6}$$ is a little less than.

So, 1.2 - (little less than 1) cannot be negative. It can neither be 0 nor 1.

OA, B
Carcass wrote:
If $$a = 2$$, $$b = 4$$, and $$c= 5$$, then $$\frac{a+b}{c} - \frac{c}{a+b} =$$

A. 1

B. 11/30

C. 0

D. -11/30

E. -1

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Joined: 18 Jun 2020
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Kudos [?]: 29 [1] , given: 9

Re: If a = 2, b = 4, and c= 5, then [#permalink]  28 Jun 2020, 15:10
1
KUDOS
Plugging the values into the equation, we get
$$\frac{6}{5 }$$ - $$\frac{ 5}{6}$$ we need to find the lowest common multiple for the denominators to compute the fraction. The lowest common multiple is 30.

Multiply $$\frac{6}{5}$$ * $$\frac{6}{6}$$ = $$\frac{36}{30}$$
multiply $$\frac{5}{6}$$ * $$\frac{5}{5}$$ = $$\frac{25}{30}$$

Then we get $$\frac{36}{30}$$ - $$\frac{25}{30}$$ = $$\frac{11}{30}$$
Re: If a = 2, b = 4, and c= 5, then   [#permalink] 28 Jun 2020, 15:10
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