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If A < 0, 10 < B < 30, and 50 < C < 80, what is the relative

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If A < 0, 10 < B < 30, and 50 < C < 80, what is the relative [#permalink] New post 20 Nov 2017, 11:06
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If A < 0, 10 < B < 30, and 50 < C < 80, what is the relative order of the reciprocals 1/A, 1/B, and 1/C?

A. 1/A < 1/B < 1/C

B. 1/A < 1/C < 1/B

C. 1/C < 1/A < 1/B

D. 1/C < 1/B < 1/A

E. 1/B < 1/C < 1/A


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Re: If A < 0, 10 < B < 30, and 50 < C < 80, what is the relative [#permalink] New post 21 Nov 2017, 13:40
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let us consider A=-2, B=20 and C=60.

Then 1/A= -1/2 => -0.5,
1/B=1/20 => .05,
1/C=1/60 => .016

Therefore, the order will be 1/A < 1/C < 1/B . Option (B) is the answer.
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Re: If A < 0, 10 < B < 30, and 50 < C < 80, what is the relative [#permalink] New post 01 Dec 2017, 21:16
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Bunuel wrote:
If A < 0, 10 < B < 30, and 50 < C < 80, what is the relative order of the reciprocals 1/A, 1/B, and 1/C?

A. 1/A < 1/B < 1/C

B. 1/A < 1/C < 1/B

C. 1/C < 1/A < 1/B

D. 1/C < 1/B < 1/A

E. 1/B < 1/C < 1/A




Here a quick thought - In fraction, the larger the denominator the smaller the value

Here A = will always be negative so is the smallest.

For B = it will range from 11 to 29 ,

whereas for C= it will range from 51 to 79.

Hence \(\frac{1}{A} < \frac{1}{C} < \frac{1}{B}\)
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Re: If A < 0, 10 < B < 30, and 50 < C < 80, what is the relative   [#permalink] 01 Dec 2017, 21:16
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