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If 9^(2x + 5) = 27^(3x − 10), then x =

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If 9^(2x + 5) = 27^(3x − 10), then x = [#permalink] New post 26 Nov 2017, 09:25
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If 9^(2x + 5) = 27^(3x − 10), then x =

A. 3
B. 6
C. 8
D. 12
E. 15


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Re: If 9^(2x + 5) = 27^(3x − 10), then x = [#permalink] New post 30 Nov 2017, 06:16
Bunuel wrote:
If 9^(2x + 5) = 27^(3x − 10), then x =

A. 3
B. 6
C. 8
D. 12
E. 15




The above equation can be written as \(3^{2(2x + 5)} = 3^{3(3x - 10)}\)

since the base are equal we can opt out, therefore we have

2(2x + 5) = 3(3x - 10)

4x + 10 = 9x - 30

x = 8
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Re: If 9^(2x + 5) = 27^(3x − 10), then x =   [#permalink] 30 Nov 2017, 06:16
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If 9^(2x + 5) = 27^(3x − 10), then x =

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