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Senior Manager Joined: 20 May 2014
Posts: 282
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If (6 + 2/x)(x - 4) = 0, and x does not equal 4, then x = [#permalink] 00:00

Question Stats: 100% (02:31) correct 0% (00:00) wrong based on 2 sessions
If $$(6 + \frac{2}{x})(x - 4) = 0$$, and x does not equal 4, then x =

(A) -6
(B) -4
(C) -1/3
(D) 1/3
(E) 3

Kudos for correct solution.
[Reveal] Spoiler: OA
Director Joined: 03 Sep 2017
Posts: 520
Followers: 1

Kudos [?]: 360 , given: 66

Re: If (6 + 2/x)(x - 4) = 0, and x does not equal 4, then x = [#permalink]
Multiplying the two expressions in parenthesis we get $$6x-24-2-\frac{8}{x}=0$$. This can be rewritten as $$6x^2-22x-8=0$$. Solving it we get two solutions $$x = 4$$ and $$x = -\frac{1}{3}$$. Given that x cannot be equal to 4 the solution is the other one, answer C
Director Joined: 20 Apr 2016
Posts: 924
WE: Engineering (Energy and Utilities)
Followers: 12

Kudos [?]: 687 , given: 149

Re: If (6 + 2/x)(x - 4) = 0, and x does not equal 4, then x = [#permalink]
Bunuel wrote:
If $$(6 + \frac{2}{x})(x - 4) = 0$$, and x does not equal 4, then x =

(A) -6
(B) -4
(C) -1/3
(D) 1/3
(E) 3

Kudos for correct solution.

$$(6 + \frac{2}{x})(x - 4) = 0$$

or we can write as = 6x^2 - 22x - 8 =0

or 3x^2 -11x - 4 = 0 (dividing by 2) which is in the form ax^2 + bx + c

Now we need the value of x , the best way in the complex equation is to use the formula, which I prefer

x= $$(-b +- \sqrt{(b^2-4*a*c)}) /2*a$$

x= $$(-11 +- \sqrt{169}) / 6$$ (where a= 3, b= -11 c = -4)

or x = $$\frac{(11+- 13)}{6}$$

Now taking positive value
x= $$\frac{(11+13)}{6}$$ = 4

Taking negative value

x= $$\frac{(11-13)}{6}$$ = $$-\frac{1}{3}$$

Since x= 4 is not possible, therefore x = $$-\frac{1}{3}$$
_________________

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Rules for Posting https://greprepclub.com/forum/rules-for ... -1083.html Re: If (6 + 2/x)(x - 4) = 0, and x does not equal 4, then x =   [#permalink] 19 Oct 2017, 01:18
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