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If (5x^2 + 65x + 60)/(x^2 +10x - 24) = (5x + 5)/(x - 2), the

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Senior Manager
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If (5x^2 + 65x + 60)/(x^2 +10x - 24) = (5x + 5)/(x - 2), the [#permalink] New post 20 Nov 2017, 11:26
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33% (00:00) correct 66% (01:56) wrong based on 3 sessions
If \(\frac{(5x^2 + 65x + 60)}{(x^2 +10x - 24)} = \frac{(5x + 5)}{(x - 2)}\), then which of the following are possible values of x?


A. −60
B. −12
C. −1
D. 1
E. 2
F. 5

[Reveal] Spoiler: OA
A, C, D, and F


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[Reveal] Spoiler: OA
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Re: If (5x^2 + 65x + 60)/(x^2 +10x - 24) = (5x + 5)/(x - 2), the [#permalink] New post 28 Nov 2017, 03:26
Need either a closer look or discerning eye to get solution on the fly :) otherwise its would literally waste much time
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Re: If (5x^2 + 65x + 60)/(x^2 +10x - 24) = (5x + 5)/(x - 2), the [#permalink] New post 29 Nov 2017, 05:46
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Bunuel wrote:
If \(\frac{(5x^2 + 65x + 60)}{(x^2 +10x - 24)} = \frac{(5x + 5)}{(x - 2)}\), then which of the following are possible values of x?


A. −60
B. −12
C. −1
D. 1
E. 2
F. 5

[Reveal] Spoiler: OA
A, C, D, and F




Here the equation can be written as-

\(\frac{5(x^2 + 13x + 12)}{(x^2 +10x - 24)} = \frac{5(x + 1)}{(x - 2)}\)

or \(\frac{(x^2 + 13x + 12)}{(x^2 +10x - 24)} = \frac{(x + 1)}{(x - 2)}\)

or \(\frac{(x + 12)(x+1)}{(x + 12)(x-2)} = \frac{(x + 1)}{(x - 2)}\)

or \(\frac{(x+1)}{(x-2)} = \frac{(x + 1)}{(x - 2)}\).

Now looking at the values we notice only when x=2, the equation is not possible, reset all are the possible values.
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Re: If (5x^2 + 65x + 60)/(x^2 +10x - 24) = (5x + 5)/(x - 2), the   [#permalink] 29 Nov 2017, 05:46
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