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#### Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here. # If (5x^2 + 65x + 60)/(x^2 +10x - 24) = (5x + 5)/(x - 2), the  Question banks Downloads My Bookmarks Reviews Important topics
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If (5x^2 + 65x + 60)/(x^2 +10x - 24) = (5x + 5)/(x - 2), the [#permalink] 00:00

Question Stats: 33% (00:00) correct 66% (01:56) wrong based on 3 sessions
If $$\frac{(5x^2 + 65x + 60)}{(x^2 +10x - 24)} = \frac{(5x + 5)}{(x - 2)}$$, then which of the following are possible values of x?

A. −60
B. −12
C. −1
D. 1
E. 2
F. 5

[Reveal] Spoiler: OA
A, C, D, and F

Kudos for correct solution.
[Reveal] Spoiler: OA
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Re: If (5x^2 + 65x + 60)/(x^2 +10x - 24) = (5x + 5)/(x - 2), the [#permalink]
Need either a closer look or discerning eye to get solution on the fly otherwise its would literally waste much time Director Joined: 20 Apr 2016
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WE: Engineering (Energy and Utilities)
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Re: If (5x^2 + 65x + 60)/(x^2 +10x - 24) = (5x + 5)/(x - 2), the [#permalink]
1
KUDOS
Bunuel wrote:
If $$\frac{(5x^2 + 65x + 60)}{(x^2 +10x - 24)} = \frac{(5x + 5)}{(x - 2)}$$, then which of the following are possible values of x?

A. −60
B. −12
C. −1
D. 1
E. 2
F. 5

[Reveal] Spoiler: OA
A, C, D, and F

Here the equation can be written as-

$$\frac{5(x^2 + 13x + 12)}{(x^2 +10x - 24)} = \frac{5(x + 1)}{(x - 2)}$$

or $$\frac{(x^2 + 13x + 12)}{(x^2 +10x - 24)} = \frac{(x + 1)}{(x - 2)}$$

or $$\frac{(x + 12)(x+1)}{(x + 12)(x-2)} = \frac{(x + 1)}{(x - 2)}$$

or $$\frac{(x+1)}{(x-2)} = \frac{(x + 1)}{(x - 2)}$$.

Now looking at the values we notice only when x=2, the equation is not possible, reset all are the possible values.
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Rules for Posting https://greprepclub.com/forum/rules-for ... -1083.html Re: If (5x^2 + 65x + 60)/(x^2 +10x - 24) = (5x + 5)/(x - 2), the   [#permalink] 29 Nov 2017, 05:46
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