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If 52x + 604 = 1400 and 151

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GRE Instructor
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Joined: 10 Apr 2015
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If 52x + 604 = 1400 and 151 [#permalink] New post 27 May 2018, 05:24
Expert's post
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Question Stats:

75% (01:00) correct 25% (04:14) wrong based on 8 sessions
If 52x + 604 = 1400 and 151 + 13y = 350, what is the value of x – y?

A) -11/13
B) -11/52
C) 0
D) 11/52
E) 11/13
[Reveal] Spoiler: OA

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Brent Hanneson – Creator of greenlighttestprep.com
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GRE Instructor
User avatar
Joined: 10 Apr 2015
Posts: 1232
Followers: 45

Kudos [?]: 1113 [0], given: 7

Re: If 52x + 604 = 1400 and 151 [#permalink] New post 28 May 2018, 05:58
Expert's post
GreenlightTestPrep wrote:
If 52x + 604 = 1400 and 151 + 13y = 350, what is the value of x – y?

A) -11/13
B) -11/52
C) 0
D) 11/52
E) 11/13


The key here is to avoid solving the two equations for x and y.

We can do this by recognizing that each term in the equation 52x + 604 = 1400 is 4 times each term in the equation 151 + 13y = 350
For example, (4)(151) = 604
And (4)(13) = 52
And (4)(350) = 1400

So, if we take 151 + 13y = 350 and multiply both sides by 4, we get the EQUIVALENT EQUATION: 604 + 52y = 1400
Rearrange to get: 52y + 604 = 1400

So, we have:
52x + 604 = 1400
52y + 604 = 1400

Since both equations are set equal to 1400, we can say: 52x + 604 = 52y + 604
Subtract 604 from both sides to get: 52x = 52y
Divide both sides by 52 to get: x = y
If x = y, then x - y = 0

Answer: C

Cheers,
Brent
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Brent Hanneson – Creator of greenlighttestprep.com
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Re: If 52x + 604 = 1400 and 151   [#permalink] 28 May 2018, 05:58
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If 52x + 604 = 1400 and 151

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