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If 42.42 = k(14 + m/50), where k and m are positive integers

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If 42.42 = k(14 + m/50), where k and m are positive integers [#permalink] New post 25 Mar 2018, 10:43
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Question Stats:

75% (00:26) correct 25% (02:49) wrong based on 12 sessions
If \(42.42 = k(14 + \frac{m}{50})\), where \(k\) and \(m\) are positive integers and \(m < 50\), then what is the value of \(k + m\) ?

(A) 6
(B) 7
(C) 8
(D) 9
(E) 10
[Reveal] Spoiler: OA

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Re: If 42.42 = k(14 + m/50), where k and m are positive integers [#permalink] New post 25 Mar 2018, 19:18
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Great question!

Start out by simplifying the equation you get
42.42*50 = (14*50 +m)*k
2121 = (700 +m)*k
Factors of 2121 = 3*7*101 => 707*3
so (700+m)*k can be write (700+7)*3
so m = 7 and k = 3 hence m+k = 10
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Re: If 42.42 = k(14 + m/50), where k and m are positive integers [#permalink] New post 28 May 2018, 22:10
42.42 = 42 + 0.42

=42 42/100 as mixed fraction or 42 21/50

3*14 = 42.
Hence k =3.
3*m = 21.

Hence m =7

On addind both we get 10.
Re: If 42.42 = k(14 + m/50), where k and m are positive integers   [#permalink] 28 May 2018, 22:10
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If 42.42 = k(14 + m/50), where k and m are positive integers

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