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#### Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here. # If |3x - 2 + 4x| > 7, which of the following is a possible  Question banks Downloads My Bookmarks Reviews Important topics
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TAGS: Active Member  Joined: 07 Jan 2018
Posts: 694
Followers: 11

Kudos [?]: 769  , given: 88

If |3x - 2 + 4x| > 7, which of the following is a possible [#permalink]
1
KUDOS 00:00

Question Stats: 81% (01:25) correct 18% (01:48) wrong based on 16 sessions
If $$|3x - 2 + 4x| > 7$$, which of the following is a possible value for x?

A. $$-\frac{2}{3}$$

B. $$-\frac{1}{2}$$

C. $$\frac{3}{4}$$

D. $$\frac{5}{4}$$

E. $$\frac{4}{3}$$
[Reveal] Spoiler: OA
Manager Joined: 26 Jan 2018
Posts: 189
GRE 1: Q165 V156 Followers: 1

Kudos [?]: 132 , given: 3

Re: If |3x - 2 + 4x| > 7, which of the following is a possible [#permalink]
Given the equation, the value of x has to be greater than 1 to satisfy the condition. So it could be 1 of the last 2 options. On plugging we would know it is the last option.
Active Member  Joined: 07 Jan 2018
Posts: 694
Followers: 11

Kudos [?]: 769 , given: 88

Re: If |3x - 2 + 4x| > 7, which of the following is a possible [#permalink]
Since the given equation is inside a modulus.
We have to take two cases while solving the equation
1st,
3x - 2 + 4x > 7
or, 7x>9
or,$$x > \frac{9}{7}$$

2nd,
3x - 2 + 4x < -7 (when multiplying both sides by -1 the inequality sign reverses)
or, 7x< -5
or, $$x < \frac{-5}{7}$$

therefore,
only option E falls withing the range since this is greater than $$\frac{9}{7}$$
_________________

This is my response to the question and may be incorrect. Feel free to rectify any mistakes
Need Practice? 20 Free GRE Quant Tests available for free with 20 Kudos Re: If |3x - 2 + 4x| > 7, which of the following is a possible   [#permalink] 09 May 2018, 23:48
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