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# If (2x + 1)(x – 5) = 2 (x^2 – 1), what is the value of x

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If (2x + 1)(x – 5) = 2 (x^2 – 1), what is the value of x [#permalink]  06 Nov 2018, 16:15
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If $$(2x + 1)(x – 5) = 2 (x^2 – 1)$$, what is the value of x?

A. $$- \frac{1}{3}$$

B. $$- \frac{1}{5}$$

C. $$0$$

D. $$\frac{1}{3}$$

E. $$\frac{1}{2}$$
[Reveal] Spoiler: OA

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Re: If (2x + 1)(x – 5) = 2 (x^2 – 1), what is the value of x [#permalink]  08 Nov 2018, 03:23
Carcass wrote:
If $$(2x + 1)(x – 5) = 2 (x^2 – 1)$$, what is the value of x?

A. $$- \frac{1}{3}$$

B. $$- \frac{1}{5}$$

C. $$0$$

D. $$\frac{1}{3}$$

E. $$\frac{1}{2}$$

Explanation::

$$(2x + 1)(x – 5) = 2 (x^2 – 1)$$

or $$2x^2 + x - 10x - 5= 2x^2 – 2$$

or $$-9x = 3$$

or $$x = -\frac{3}{9} = - \frac{1}{3}$$
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Re: If (2x + 1)(x – 5) = 2 (x^2 – 1), what is the value of x   [#permalink] 08 Nov 2018, 03:23
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# If (2x + 1)(x – 5) = 2 (x^2 – 1), what is the value of x

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