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If 2^2p-10=2(2^9-2p), then p= [#permalink]
Expert's post 00:00

Question Stats: 92% (00:57) correct 7% (03:34) wrong based on 13 sessions
If $$2^{2p-10}=2(2^{9-2p})$$, then p=

A. 5

B. 3

C. 0

D. -1

E. -2
[Reveal] Spoiler: OA

_________________ Intern Joined: 07 Aug 2016
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Re: If 2^2p-10=2(2^9-2p), then p= [#permalink]
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Carcass wrote:
If $$2^{2p-10}=2(2^{9-2p})$$, then p=

A. 5

B. 3

C. 0

D. -1

E. -2

Easiest way is to back-substitute.

p = 5

2^(10-10) = 2 (2^(9 - 10))

2^0 = 2* 2^-1

2^0 = 2/2

1 = 1

Answer choice A
Manager Joined: 23 Oct 2018
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Re: If 2^2p-10=2(2^9-2p), then p= [#permalink]
it was the same question as in the exam
Manager Joined: 23 Oct 2018
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Re: If 2^2p-10=2(2^9-2p), then p= [#permalink]
can you provide the exmpalantion
Intern Joined: 02 Jan 2019
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Re: If 2^2p-10=2(2^9-2p), then p= [#permalink]
This question tests the rules of exponents.

Remember that a^x * a^y = a^(x+y)

Sometimes they also create a question with a^x * a^x = (?) to try to trick you. Just follow the rule above. [a^x * a^x = a^(x+x)] Re: If 2^2p-10=2(2^9-2p), then p=   [#permalink] 10 Feb 2019, 09:20
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