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If 125^1448^8 were expressed as an integer, how many

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If 125^1448^8 were expressed as an integer, how many [#permalink] New post 25 Aug 2018, 14:51
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Question Stats:

80% (01:12) correct 20% (00:37) wrong based on 35 sessions
If \(125^{14}48^8\) were expressed as an integer, how many consecutive zeros would that integer have immediately to the left of its decimal point?

(A) 22
(B) 32
(C) 42
(D) 50
(E) 112
[Reveal] Spoiler: OA

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Re: If 125^1448^8 were expressed as an integer, how many [#permalink] New post 25 Aug 2018, 23:10
It seems question should be reworded as there is no decimal point when the expression is expanded and zeros occur to the right of the last non zero digit.
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Re: If 125^1448^8 were expressed as an integer, how many [#permalink] New post 18 Jun 2020, 04:10
sandy wrote:
If \(125^{14}48^8\) were expressed as an integer, how many consecutive zeros would that integer have immediately to the left of its decimal point?

(A) 22
(B) 32
(C) 42
(D) 50
(E) 112


Since \(125=5^3\) and 48=16*3 -> \((2)^4*3\)
\((5^3)^{14})\) X \(((2^4)*3)^8\)
\(5^{42}*2^{32}*3^8\)

Since 10 is divisible by 2 and 5, the greatest common number of those values seems to be 32
Re: If 125^1448^8 were expressed as an integer, how many   [#permalink] 18 Jun 2020, 04:10
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If 125^1448^8 were expressed as an integer, how many

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