Bunuel wrote:
If \(0 < 10^n < 1,000,000\), where n is a non-negative integer, what is the greatest value of \(\frac{1}{2^n}\)?
A. 1/2
B. 1
C. 5
D. 32
E. 64
Kudos for correct solution.
In the fraction, the greater the value of n the lower the \(\frac{1}{2^n}\).
here the value of n should be between 0 to 5
so \(\frac{1}{2^0}\) = 1
\(\frac{1}{2^1}\) = 0.5
\(\frac{1}{2^2}\) = 0.25
similarly \(\frac{1}{2^5}\) = 0.031.
Hence option B is correct.
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33% (00:00) correct
