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If 0 < 10^n < 1,000,000, where n is a non-negative integer,

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Senior Manager
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If 0 < 10^n < 1,000,000, where n is a non-negative integer, [#permalink] New post 01 Oct 2017, 22:17
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33% (00:00) correct 66% (01:01) wrong based on 3 sessions
If \(0 < 10^n < 1,000,000\), where n is a non-negative integer, what is the greatest value of \(\frac{1}{2^n}\)?


A. 1/2
B. 1
C. 5
D. 32
E. 64

Kudos for correct solution.
[Reveal] Spoiler: OA
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Joined: 20 Apr 2016
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Re: If 0 < 10^n < 1,000,000, where n is a non-negative integer, [#permalink] New post 01 Oct 2017, 23:10
Bunuel wrote:
If \(0 < 10^n < 1,000,000\), where n is a non-negative integer, what is the greatest value of \(\frac{1}{2^n}\)?


A. 1/2
B. 1
C. 5
D. 32
E. 64

Kudos for correct solution.


In the fraction, the greater the value of n the lower the \(\frac{1}{2^n}\).

here the value of n should be between 0 to 5

so \(\frac{1}{2^0}\) = 1

\(\frac{1}{2^1}\) = 0.5

\(\frac{1}{2^2}\) = 0.25

similarly \(\frac{1}{2^5}\) = 0.031.

Hence option B is correct.
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Re: If 0 < 10^n < 1,000,000, where n is a non-negative integer,   [#permalink] 01 Oct 2017, 23:10
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If 0 < 10^n < 1,000,000, where n is a non-negative integer,

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