In the fraction, the greater the value of n the lower the \(\frac{1}{2^n}\).

here the value of n should be between 0 to 5

so \(\frac{1}{2^0}\) = 1

\(\frac{1}{2^1}\) = 0.5

\(\frac{1}{2^2}\) = 0.25

similarly \(\frac{1}{2^5}\) = 0.031.

Hence option B is correct.
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