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# QUANTITATIVE SECTION 10 :Ques 5 of 20 ID: Q02-83 ( GGREClub)

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QUANTITATIVE SECTION 10 :Ques 5 of 20 ID: Q02-83 ( GGREClub) [#permalink]  20 Sep 2017, 04:38
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0% (00:00) correct 0% (00:00) wrong based on 0 sessions
ABCD is a rectangle. R is the midpoint of DC.

 Quantity A Quantity B Area of ΔΔDPC Twice the area of ΔΔDQR

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

But THE ANS should be C-

because

Area of Triangle DPC = 1/2(DC)*(BC)

Twice the Area of Triangle DQR = 2 *[1/2(DC/2)*(BC)] = [1/2(DC)*(BC)] = Area of Triangle DPC

Plz clarify
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Last edited by Carcass on 20 Sep 2017, 05:06, edited 1 time in total.
Edited by Carcass
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Re: QUANTITATIVE SECTION 10 :Ques 5 of 20 ID: Q02-83 ( GGREClub) [#permalink]  23 Sep 2017, 08:39
1
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Expert's post
pranab01 wrote:
ABCD is a rectangle. R is the midpoint of DC.

 Quantity A Quantity B Area of ΔΔDPC Twice the area of ΔΔDQR

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

But THE ANS should be C-

because

Area of Triangle DPC = 1/2(DC)*(BC)

Twice the Area of Triangle DQR = 2 *[1/2(DC/2)*(BC)] = [1/2(DC)*(BC)] = Area of Triangle DPC

Plz clarify

Both triangles have the same height, and the length of the base of ΔDPC is TWICE that of ΔDQR
So, the area of ΔDPC is TWICE the area of ΔDQR
So, of we DOUBLE the area of ΔDQR (quantity B), then the two quantities will be equal.

Cheers,
Brent
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Re: QUANTITATIVE SECTION 10 :Ques 5 of 20 ID: Q02-83 ( GGREClub)   [#permalink] 23 Sep 2017, 08:39
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