pranab01 wrote:
ABCD is a rectangle. R is the midpoint of DC.
Quantity A |
Quantity B |
Area of ΔΔDPC |
Twice the area of ΔΔDQR |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Answer given is DBut THE ANS should be C- because
Area of Triangle DPC = 1/2(DC)*(BC)
Twice the Area of Triangle DQR = 2 *[1/2(DC/2)*(BC)] = [1/2(DC)*(BC)] = Area of Triangle DPC
Plz clarify
Your analysis is perfect.
Both triangles have the same height, and the length of the base of ΔDPC is TWICE that of ΔDQR
So, the area of ΔDPC is TWICE the area of ΔDQR
So, of we DOUBLE the area of ΔDQR (quantity B), then the two quantities will be equal.
Answer: C
Cheers,
Brent
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Brent Hanneson – Founder of greenlighttestprep.com
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