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GRE Practice Question-|x^3| < 64

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GRE Practice Question-|x^3| < 64 [#permalink] New post 30 Apr 2015, 14:53
00:00

Question Stats:

85% (01:09) correct 14% (00:00) wrong based on 7 sessions
|x^3| < 64

Quantity A
-x


Quantity B
|-x|

??? Solution?
[Reveal] Spoiler: OA
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Joined: 07 Jun 2014
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GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
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Re: GRE Practice Question [#permalink] New post 02 May 2015, 08:31
Expert's post
Osira wrote:
|x^3| < 64

Quantity A
-x


Quantity B
|-x|

??? Solution?


Cannot be determined!
Take x=7 the first inequality is satified and Quantity B is greater than Quantity A. Now take -7 the first inequality is satified and Quantity A= Quantity B.

So it cannot be determined!
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Re: GRE Practice Question [#permalink] New post 03 May 2015, 06:06
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Expert's post
sandy wrote:
Osira wrote:
|x^3| < 64

Quantity A
-x


Quantity B
|-x|

??? Solution?


Cannot be determined!
Take x=7 the first inequality is satified and Quantity B is greater than Quantity A. Now take -7 the first inequality is satified and Quantity A= Quantity B.

So it cannot be determined!


Hi Sandy,

Be careful; x = 7 does not satisfy the inequality |x^3| < 64

Cheers,
Brent
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Brent Hanneson – Creator of greenlighttestprep.com
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Re: GRE Practice Question [#permalink] New post 03 May 2015, 06:12
Expert's post
Osira wrote:
|x^3| < 64

Quantity A
-x


Quantity B
|-x|


One of my favorite QC strategies is called "Looking for Equality" (free video on this topic here: http://www.greenlighttestprep.com/modul ... on?id=1099).
In this strategy, I first look for values of x such that the two quantities are equal.
I see that, x = 0 satisfies the inequality |x^3| < 64
Here, we get:
Quantity A: -x = -0 = 0
Quantity B: |-x| = |-0| = 0
Since the 2 quantities are EQUAL in this case, the correct answer is EITHER C or D
Now, try another value of x.

Well, x = 1 satisfies the inequality |x^3| < 64
Here, we get:
Quantity A: -x = -1 = -1
Quantity B: |-x| = |-1| = 1
Here, the 2 quantities are NOT EQUAL

So, the correct answer is D

Cheers,
Brent
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Re: GRE Practice Question [#permalink] New post 03 May 2015, 22:00
Let's take X=-7
both quantities are same.....
here we go C, And ignore A,B
,
When X=7
quantity B is greater
we have already ignored A,B And C option is gone.
we only left with D...........
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Re: GRE Practice Question [#permalink] New post 04 May 2015, 08:02
Expert's post
GRE wrote:
Let's take X=-7
both quantities are same.....
here we go C, And ignore A,B
,
When X=7
quantity B is greater
we have already ignored A,B And C option is gone.
we only left with D...........


Be careful.
The question tells us that |x^3| < 64
So, if we choose a value of x to test, that value must meet the given condition that |x^3| < 64
In this case, |7^3| is not less than 64
So, we can't use the value x = 7.

Cheers,
Brent
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Re: GRE Practice Question [#permalink] New post 05 May 2015, 00:33
#GreenlightTestPrep thanks for correcting..............
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Re: GRE Practice Question [#permalink] New post 16 Jan 2018, 23:57
GreenlightTestPrep wrote:
sandy wrote:
Osira wrote:
|x^3| < 64

Quantity A
-x


Quantity B
|-x|

??? Solution?


Cannot be determined!
Take x=7 the first inequality is satified and Quantity B is greater than Quantity A. Now take -7 the first inequality is satified and Quantity A= Quantity B.

So it cannot be determined!


Hi Sandy,

Be careful; x = 7 does not satisfy the inequality |x^3| < 64

Cheers,
Brent


thanks for reminder! I actually made the same mistake too
Re: GRE Practice Question   [#permalink] 16 Jan 2018, 23:57
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