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GRE Math Challenge #93-For every positive integer

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GRE Math Challenge #93-For every positive integer [#permalink] New post 09 May 2015, 11:38
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For every positive integer n greater than 1, n! Is defined as the product of the first n positive integers,
For example, 4! = (1) (2) (3) (4) = 24. What is the value of 12!/ 10!

(A) 2
(B) 66
(C) 121
(D) 132
(E) 144
[Reveal] Spoiler: OA

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Sandy
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Director
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Re: GRE Math Challenge #93-For every positive integer [#permalink] New post 18 Dec 2017, 07:09
sandy wrote:
For every positive integer n greater than 1, n! Is defined as the product of the first n positive integers,
For example, 4! = (1) (2) (3) (4) = 24. What is the value of 12!/ 10!

(A) 2
(B) 66
(C) 121
(D) 132
(E) 144


Here

\(\frac{12!}{10!}\) = \(\frac{(12 * 11 * 10!)}{10!}\)= 132
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Re: GRE Math Challenge #93-For every positive integer [#permalink] New post 19 Dec 2017, 18:37
pranab01 wrote:
sandy wrote:
For every positive integer n greater than 1, n! Is defined as the product of the first n positive integers,
For example, 4! = (1) (2) (3) (4) = 24. What is the value of 12!/ 10!

(A) 2
(B) 66
(C) 121
(D) 132
(E) 144


Here

\(\frac{12!}{10!}\) = \(\frac{(12 * 11 * 10!)}{10!}\)= 121



the answer of (12*11*10)/10! should be 132! answer is worng
Director
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Re: GRE Math Challenge #93-For every positive integer [#permalink] New post 19 Dec 2017, 21:09
Peter wrote:


the answer of (12*11*10)/10! should be 132! answer is worng


Thanks - corrected

However while solving factorial ques, kindly donot put the "!" in the answer as this represent a factorial sign
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Re: GRE Math Challenge #93-For every positive integer   [#permalink] 19 Dec 2017, 21:09
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GRE Math Challenge #93-For every positive integer

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