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# GRE Math Challenge #93-For every positive integer

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Joined: 07 Jun 2014
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GRE Math Challenge #93-For every positive integer [#permalink]  09 May 2015, 11:38
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Question Stats:

100% (00:30) correct 0% (00:00) wrong based on 2 sessions
For every positive integer n greater than 1, n! Is defined as the product of the first n positive integers,
For example, 4! = (1) (2) (3) (4) = 24. What is the value of 12!/ 10!

(A) 2
(B) 66
(C) 121
(D) 132
(E) 144
[Reveal] Spoiler: OA

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Sandy
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Director
Joined: 20 Apr 2016
Posts: 756
Followers: 6

Kudos [?]: 511 [0], given: 94

Re: GRE Math Challenge #93-For every positive integer [#permalink]  18 Dec 2017, 07:09
sandy wrote:
For every positive integer n greater than 1, n! Is defined as the product of the first n positive integers,
For example, 4! = (1) (2) (3) (4) = 24. What is the value of 12!/ 10!

(A) 2
(B) 66
(C) 121
(D) 132
(E) 144

Here

$$\frac{12!}{10!}$$ = $$\frac{(12 * 11 * 10!)}{10!}$$= 132
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Manager
Joined: 27 Sep 2017
Posts: 112
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Re: GRE Math Challenge #93-For every positive integer [#permalink]  19 Dec 2017, 18:37
pranab01 wrote:
sandy wrote:
For every positive integer n greater than 1, n! Is defined as the product of the first n positive integers,
For example, 4! = (1) (2) (3) (4) = 24. What is the value of 12!/ 10!

(A) 2
(B) 66
(C) 121
(D) 132
(E) 144

Here

$$\frac{12!}{10!}$$ = $$\frac{(12 * 11 * 10!)}{10!}$$= 121

Director
Joined: 20 Apr 2016
Posts: 756
Followers: 6

Kudos [?]: 511 [0], given: 94

Re: GRE Math Challenge #93-For every positive integer [#permalink]  19 Dec 2017, 21:09
Peter wrote:

Thanks - corrected

However while solving factorial ques, kindly donot put the "!" in the answer as this represent a factorial sign
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Re: GRE Math Challenge #93-For every positive integer   [#permalink] 19 Dec 2017, 21:09
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