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GRE Math Challenge #92-Solve 3 - 2[ 5 - 7*(3+2) ]=

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GRE 1: Q167 V156
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GRE Math Challenge #92-Solve 3 - 2[ 5 - 7*(3+2) ]= [#permalink] New post 09 May 2015, 11:37
Expert's post
00:00

Question Stats:

75% (00:17) correct 25% (00:13) wrong based on 8 sessions
\(3 - 2[ 5 - 7*(3+2) ]=\)

(A) –30
(B) –10
(C) 23
(D) 63
(E) 77
[Reveal] Spoiler: OA

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Re: GRE Math Challenge #92-Solve 3 - 2[ 5 - 7*(3+2) ]= [#permalink] New post 18 Dec 2017, 06:33
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sandy wrote:
\(3 - 2[ 5 - 7*(3+2) ]=\)

(A) –30
(B) –10
(C) 23
(D) 63
(E) 77



Here we need to follow the BODMAS RULE

B = BRACKET (...)
O = ORDERS(numbers involving powers or square roots)
M = MULTIPLICATION
A = ADDITION
S= SUBTRACTION

Hence by solving the above equation comes = 63. i.e option D
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Re: GRE Math Challenge #92-Solve 3 - 2[ 5 - 7*(3+2) ]= [#permalink] New post 08 Mar 2018, 00:53
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I think the ans should be A.

I assume \(*\) here is multiplication. then,

\(3+2 = 5*7 = 35\)
\(5-35 = -30\)
Outside bracket we have \(3-2 =1 so 1*(-30) = -30\)
Just to make sure I put the given syntax as it is in the desktop calculator and it gives \(-30\)
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Re: GRE Math Challenge #92-Solve 3 - 2[ 5 - 7*(3+2) ]= [#permalink] New post 08 Mar 2018, 05:54
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I believe the answer to be 63

3-2[5-7(3+2)]
3-2[5-7(5)]
3-2[5-35]
3-2[-30]
3+60
63

PEMDAS is key here
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Re: GRE Math Challenge #92-Solve 3 - 2[ 5 - 7*(3+2) ]= [#permalink] New post 08 Mar 2018, 14:33
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Expert's post
Jchen14 is perfectly right.

Following step by step the pemdas you forgot that minus * minus is positive @amorphous

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Re: GRE Math Challenge #92-Solve 3 - 2[ 5 - 7*(3+2) ]=   [#permalink] 08 Mar 2018, 14:33
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