It is currently 22 Apr 2019, 14:44

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# GRE Math Challenge #89-A health food store prepares

Author Message
TAGS:
GRE Prep Club Legend
Joined: 07 Jun 2014
Posts: 4857
GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
Followers: 106

Kudos [?]: 1825 [0], given: 397

GRE Math Challenge #89-A health food store prepares [#permalink]  09 May 2015, 11:36
Expert's post
00:00

Question Stats:

99% (01:31) correct 0% (00:00) wrong based on 7 sessions
A health food store prepares a breakfast food that consists of oats, raisins, and nuts mixed in the ratio 9:2:1, respectively, by weight. If the nuts in the mixture weigh 9.2 pounds, how many pounds does the total mixture weigh?

(A) 82.2
(B) 92.2
(C) 101. 2
(D) 110.4
(E) 165.6
[Reveal] Spoiler: OA

_________________

Sandy
If you found this post useful, please let me know by pressing the Kudos Button

Try our free Online GRE Test

Director
Joined: 20 Apr 2016
Posts: 855
WE: Engineering (Energy and Utilities)
Followers: 11

Kudos [?]: 631 [0], given: 134

Re: GRE Math Challenge #89-A health food store prepares [#permalink]  18 Dec 2017, 06:23
sandy wrote:
A health food store prepares a breakfast food that consists of oats, raisins, and nuts mixed in the ratio 9:2:1, respectively, by weight. If the nuts in the mixture weigh 9.2 pounds, how many pounds does the total mixture weigh?

(A) 82.2
(B) 92.2
(C) 101. 2
(D) 110.4
(E) 165.6

Here the weight of Nuts = 9.2 pounds and we need to find out the total weight of the mixture.

Let the total weight of mixture be = T

since oats:raisins : nuts = 9:2:1

i.e 9 parts of Total (T)+ 2 parts of Total (T) + 1 parts of total (T) = 12 T

Part/ Whole = $$\frac{Nuts}{Total mixture}$$ = $$\frac{9.2}{Total weight}$$

or $$\frac{T}{12T}$$= $$\frac{9.2}{Total weight}$$

or Total weight = 110.4 i.e total weight of the mixture is 110.4 pounds
_________________

If you found this post useful, please let me know by pressing the Kudos Button

Rules for Posting https://greprepclub.com/forum/rules-for ... -1083.html

Intern
Joined: 11 Feb 2019
Posts: 7
Followers: 0

Kudos [?]: 0 [0], given: 0

Re: GRE Math Challenge #89-A health food store prepares [#permalink]  11 Feb 2019, 05:22
pranab01 wrote:
sandy wrote:
A health food store prepares a breakfast food that consists of oats, raisins, and nuts mixed in the ratio 9:2:1, respectively, by weight. If the nuts in the mixture weigh 9.2 pounds, how many pounds does the total mixture weigh?

(A) 82.2
(B) 92.2
(C) 101. 2
(D) 110.4
(E) 165.6

Here the weight of Nuts = 9.2 pounds and we need to find out the total weight of the mixture.

Let the total weight of mixture be = T

since oats:raisins : nuts = 9:2:1

i.e 9 parts of Total (T)+ 2 parts of Total (T) + 1 parts of total (T) = 12 T

Part/ Whole = $$\frac{Nuts}{Total mixture}$$ = $$\frac{9.2}{Total weight}$$

or $$\frac{T}{12T}$$= $$\frac{9.2}{Total weight}$$

or Total weight = 110.4 i.e total weight of the mixture is 110.4 pounds

I think that Total weight = 110.4 is true answer
Re: GRE Math Challenge #89-A health food store prepares   [#permalink] 11 Feb 2019, 05:22
Display posts from previous: Sort by