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# GRE Math Challenge #88-if point (a, b), shown,

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GRE Math Challenge #88-if point (a, b), shown, [#permalink]  09 May 2015, 11:35
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Question Stats:

80% (00:49) correct 20% (02:06) wrong based on 5 sessions
In the rectangular coordinate system above, if point (a, b), shown, and the two points (4a, b) and (2a, 2b), not shown, were connected by straight lines, then the area of the resulting triangular region, in terms of a and b, would be

(A) ab/2
(B) ab
(C) 3ab/2
(D) 2ab
(E) 4ab
[Reveal] Spoiler: OA

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Sandy
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Re: GRE Math Challenge #88-if point (a, b), shown, [#permalink]  18 Dec 2017, 05:26
sandy wrote:
In the rectangular coordinate system above, if point (a, b), shown, and the two points (4a, b) and (2a, 2b), not shown, were connected by straight lines, then the area of the resulting triangular region, in terms of a and b, would be

(A) ab/2
(B) ab
(C) 3ab/2
(D) 2ab
(E) 4ab

Here we can draw the diagram as below.

The distance between the co-ordinates (a,b) and (4a,b) is 3a, which is the base of the triangle.

We know the height of the triangle is always perpendicular to the base, so the height = 2b - b =b

Hence the Area of triangle = $$\frac{1}{2}$$* b * h = $$\frac{1}{2}$$ * 3a * b =$$\frac{3ab}{2}$$
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Re: GRE Math Challenge #88-if point (a, b), shown, [#permalink]  08 Mar 2018, 00:56
sandy wrote:
In the rectangular coordinate system above, if point (a, b), shown, and the two points (4a, b) and (2a, 2b), not shown, were connected by straight lines, then the area of the resulting triangular region, in terms of a and b, would be

(A) ab/2
(B) ab
(C) 3ab/2
(D) 2ab
(E) 4ab

Diagram is missing
Re: GRE Math Challenge #88-if point (a, b), shown,   [#permalink] 08 Mar 2018, 00:56
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