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# GRE Math Challenge #79-developer has land that has x feet of

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GRE Math Challenge #79-developer has land that has x feet of [#permalink]  03 May 2015, 01:43
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Question Stats:

100% (00:52) correct 0% (00:00) wrong based on 2 sessions
A developer has land that has x feet of lake frontage. The land is to be subdivided into lots, each of which is to have either 80 feet or 100 feet of Lake Frontage. If (1/9) of the lots are to have 80 feet of frontage each and the remaining 40 lots are to have 100 feet of frontage each, what is the value of x?

(A) 400
(B) 3,200
(C) 3,700
(D) 4,400
(E) 4,760
[Reveal] Spoiler: OA

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Re: GRE Math Challenge #79-developer has land that has x feet of [#permalink]  14 Dec 2017, 05:08
sandy wrote:
A developer has land that has x feet of lake frontage. The land is to be subdivided into lots, each of which is to have either 80 feet or 100 feet of Lake Frontage. If (1/9) of the lots are to have 80 feet of frontage each and the remaining 40 lots are to have 100 feet of frontage each, what is the value of x?

(A) 400
(B) 3,200
(C) 3,700
(D) 4,400
(E) 4,760

Here
First we need to find the total Lots after that we can find the value of x

Let total lots = P
lots with 80 feet = $$\frac{1}{9}$$

SO the lots with 100 feet = $$\frac{8}{9}$$

Therefore lots for 100 feet = $$\frac{8}{9} * p$$ = 40 (since the remaining 40 plot are to have 100 feet)

or p = 45 lots

Now Total feet x = total lot for 80 feet + total lot for 100 feet

= $${(\frac{1}{9} * 45) * 80}$$ $$+$$ $${(\frac{8}{9} * 45) * 100}$$ = 4400
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Re: GRE Math Challenge #79-developer has land that has x feet of   [#permalink] 14 Dec 2017, 05:08
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