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# GRE Math Challenge #78-numbers in the list above are ordered

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GRE Math Challenge #78-numbers in the list above are ordered [#permalink]  03 May 2015, 01:43
Expert's post
00:00

Question Stats:

84% (00:26) correct 15% (01:22) wrong based on 13 sessions
$$3, 7, 9, 14, x$$

The numbers in the list above are ordered from least to greatest. If the average (arithmetic mean) is 2 greater than the median, what is the value of x?

(A) 22
(B) 20
(C) 17
(D) 16
(E) 15
[Reveal] Spoiler: OA

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Sandy
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Re: GRE Math Challenge #78-numbers in the list above are ordered [#permalink]  18 Jul 2016, 04:38
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Mean is 9 ,so average will be 9+2=11;
3+7+9+14+x=11*5
x=55-33=22
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Re: GRE Math Challenge #78-numbers in the list above are ordered [#permalink]  10 Aug 2016, 06:55
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Expert's post
sandy wrote:
$$3, 7, 9, 14, x$$

The numbers in the list above are ordered from least to greatest. If the average (arithmetic mean) is 2 greater than the median, what is the value of x?
(A) 22
(B) 20
(C) 17
(D) 16
(E) 15

Since we're told the numbers are ordered from least to greatest, we can see that the MEDIAN = 9
We're told that the average (arithmetic mean) is 2 greater than the median
So, the MEAN = 11

In other words, (3 + 7 + 9 + 14 + x)/5 = 11
Multiply both sides by 11 to get: 3 + 7 + 9 + 14 + x = 55
Simplify: 33 + x = 55
Solve: x = 22

[Reveal] Spoiler:
A

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Re: GRE Math Challenge #78-numbers in the list above are ordered   [#permalink] 10 Aug 2016, 06:55
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