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GRE Math Challenge #78-numbers in the list above are ordered

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GRE Math Challenge #78-numbers in the list above are ordered [#permalink] New post 03 May 2015, 01:43
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Question Stats:

84% (00:26) correct 15% (01:22) wrong based on 13 sessions
\(3, 7, 9, 14, x\)


The numbers in the list above are ordered from least to greatest. If the average (arithmetic mean) is 2 greater than the median, what is the value of x?

(A) 22
(B) 20
(C) 17
(D) 16
(E) 15
[Reveal] Spoiler: OA

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Re: GRE Math Challenge #78-numbers in the list above are ordered [#permalink] New post 18 Jul 2016, 04:38
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Mean is 9 ,so average will be 9+2=11;
3+7+9+14+x=11*5
x=55-33=22
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Re: GRE Math Challenge #78-numbers in the list above are ordered [#permalink] New post 10 Aug 2016, 06:55
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sandy wrote:
\(3, 7, 9, 14, x\)


The numbers in the list above are ordered from least to greatest. If the average (arithmetic mean) is 2 greater than the median, what is the value of x?
(A) 22
(B) 20
(C) 17
(D) 16
(E) 15


Since we're told the numbers are ordered from least to greatest, we can see that the MEDIAN = 9
We're told that the average (arithmetic mean) is 2 greater than the median
So, the MEAN = 11

In other words, (3 + 7 + 9 + 14 + x)/5 = 11
Multiply both sides by 11 to get: 3 + 7 + 9 + 14 + x = 55
Simplify: 33 + x = 55
Solve: x = 22

Answer:
[Reveal] Spoiler:
A


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Re: GRE Math Challenge #78-numbers in the list above are ordered   [#permalink] 10 Aug 2016, 06:55
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