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GRE Math Challenge#7- 10 foot ladder leaning

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Director
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Joined: 16 May 2014
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GRE 1: Q165 V161
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GRE Math Challenge#7- 10 foot ladder leaning [#permalink] New post 05 Aug 2014, 03:39
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Question Stats:

99% (01:54) correct 0% (00:00) wrong based on 7 sessions
The following is a bit hard Geometry question.
Attachment:
q2.png
q2.png [ 37.76 KiB | Viewed 1495 times ]
[Reveal] Spoiler: OA

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Re: GRE Math Challenge#7 [#permalink] New post 06 Aug 2014, 01:05
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Considering the original condition, a 10 ft. ladder resting on a wall with its top 8 ft. above the ground. A right angle triangle with hypotenuse of 10 ft. (length of ladder) and height of 8 ft. can be drawn, by applying pythagoras theorem we can derive the base of the triangle as 6 ft.
After the ladder has shifted by 1 ft. away from the wall (as shown), we can conclude that the top of the ladder has also slides down the wall (lets assume that distance as "d"). In the new triangle, the hypotenuse remains 10 ft., the base becomes (6+1) = 7 ft. and the height will be now (8-d) ft. Again on applying pythagoras theorem, we can calculate d=~0.86 ft., which is less than 1.

Hence, column (A) is greater than (B). Right answer is (A)
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Re: GRE Math Challenge#7- 10 foot ladder leaning [#permalink] New post 16 Jan 2018, 20:10
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What is quantity A? it state a brunch of fact but don't know what the object they want us to compare to?
Re: GRE Math Challenge#7- 10 foot ladder leaning   [#permalink] 16 Jan 2018, 20:10
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GRE Math Challenge#7- 10 foot ladder leaning

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