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# GRE Math Challenge#7- 10 foot ladder leaning

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Director
Joined: 16 May 2014
Posts: 595
GRE 1: Q165 V161
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Kudos [?]: 457 [1] , given: 64

GRE Math Challenge#7- 10 foot ladder leaning [#permalink]  05 Aug 2014, 03:39
1
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Expert's post
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Question Stats:

99% (01:54) correct 0% (00:00) wrong based on 7 sessions
The following is a bit hard Geometry question.
Attachment:

q2.png [ 37.76 KiB | Viewed 1622 times ]
[Reveal] Spoiler: OA

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Intern
Joined: 18 Jun 2014
Posts: 42
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Kudos [?]: 26 [2] , given: 15

Re: GRE Math Challenge#7 [#permalink]  06 Aug 2014, 01:05
2
KUDOS
Considering the original condition, a 10 ft. ladder resting on a wall with its top 8 ft. above the ground. A right angle triangle with hypotenuse of 10 ft. (length of ladder) and height of 8 ft. can be drawn, by applying pythagoras theorem we can derive the base of the triangle as 6 ft.
After the ladder has shifted by 1 ft. away from the wall (as shown), we can conclude that the top of the ladder has also slides down the wall (lets assume that distance as "d"). In the new triangle, the hypotenuse remains 10 ft., the base becomes (6+1) = 7 ft. and the height will be now (8-d) ft. Again on applying pythagoras theorem, we can calculate d=~0.86 ft., which is less than 1.

Hence, column (A) is greater than (B). Right answer is (A)
Manager
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Kudos [?]: 16 [1] , given: 20

Re: GRE Math Challenge#7- 10 foot ladder leaning [#permalink]  16 Jan 2018, 20:10
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What is quantity A? it state a brunch of fact but don't know what the object they want us to compare to?
Re: GRE Math Challenge#7- 10 foot ladder leaning   [#permalink] 16 Jan 2018, 20:10
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# GRE Math Challenge#7- 10 foot ladder leaning

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