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GRE Math Challenge #68-If x is 1, 2, or 3 and y

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GRE Math Challenge #68-If x is 1, 2, or 3 and y [#permalink] New post 03 May 2015, 01:23
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Question Stats:

33% (00:01) correct 66% (00:30) wrong based on 6 sessions
If x is 1, 2, or 3 and y is either 2 or 4, then the product xy can have how many different possible values?

A. Three
B. Four
C. Five
D. Six
E. Seven
[Reveal] Spoiler: OA

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Re: GRE Math Challenge #68-If x is 1, 2, or 3 and y [#permalink] New post 12 Dec 2017, 11:13
sandy wrote:
If x is 1, 2, or 3 and y is either 2 or 4, then the product xy can have how many different possible values?

A. Three
B. Four
C. Five
D. Six
E. Seven


Here let us put the values of x and y and find different possible values

xy= 1 * 2 = 2
xy= 1 * 4 = 4


xy= 2 * 2 = 4
xy= 2 * 4 = 8
xy= 3 * 2 = 6
xy= 3 * 4 = 12

Hence there are 5 different values, because the value 4 appeared twice
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Re: GRE Math Challenge #68-If x is 1, 2, or 3 and y [#permalink] New post 10 May 2018, 10:34
I think we can also add 3 x's and 2 y's to get the desired option... I think the question can also be solved by combinatronics. .Please clarify.
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Re: GRE Math Challenge #68-If x is 1, 2, or 3 and y [#permalink] New post 11 May 2018, 04:26
As 4 is common when trying out with all the number combinations, it has to be counted only once. Hence the answer.
Re: GRE Math Challenge #68-If x is 1, 2, or 3 and y   [#permalink] 11 May 2018, 04:26
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GRE Math Challenge #68-If x is 1, 2, or 3 and y

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