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Re: GRE Math Challenge #62- (24/23) + (101/100) or 2 [#permalink]
17 Jan 2018, 22:56

2

This post received KUDOS

this question should be solved without using the calculator 24>23 hence 24/23 is greater than 1 101/100 = 1.01 sum= 1.01 + a number greater than 1. end result>2 (A)
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Re: GRE Math Challenge #62- (24/23) + (101/100) or 2 [#permalink]
20 May 2018, 02:04

Just by looking at the problem one can discern that since the denominator is greater than numerator the quotient (solution of division ) has to 1.some decimal.

As we notice both the factions when added will result 2.(something) in decimals which is greater than 2.

Therefore option A is correct.

greprepclubot

Re: GRE Math Challenge #62- (24/23) + (101/100) or 2
[#permalink]
20 May 2018, 02:04